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Elena L [17]
2 years ago
13

Janice spent $54 to buy some pairs of pants. Each pair of pants cost the same whole dollar amount. How many pairs of pants could

she have bought
Mathematics
1 answer:
Naddika [18.5K]2 years ago
7 0
6 pants @ $ 9 each. Or 9 pants @ $ 6 each.
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The monthly salary of Mr. Sachdev gets increased by 5%, thereby his salary becomes Rs. 15,120 per annum, His earlier monthly sal
Elan Coil [88]
1. x = 15120/12 = 1260 (monthly salary)
2. 1200 x 0.05 = 60 (raise)
Check: 1200+60=1260
6 0
2 years ago
1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
2 years ago
Divide 42 in a ratio of 1:2:3
Vilka [71]

the ratio in which 42 should be divided is 1:2:3

the sum of the parts of the ratio is - 1 + 2 + 3 = 6

this means that there's a sum of 6 parts

so we need to find how much 1 part is equivalent to

if 6 parts are equivalent to 42

then 1 part is equivalent to - 42/6 = 7

so the ratio should be 1:2:3

1 part - 7

2 parts - 7 x 2 = 14

3 parts - 7 x 3 = 21

therefore 42 divided into 1:2:3 ratio is as follows

7 : 14 : 12

4 0
2 years ago
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A local university wanted to understand what students prefer to eat during finals. They asked 1,000 students, "Do you prefer chi
kompoz [17]
Given that the person is female, the universe is reduced to 219 + 192 + 119 = 530 people.

The number of women that prefer pizza is 119.

Then the probability is 119/530 *100 = 22.5%
3 0
2 years ago
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Which statement correctly describes the characterization in this excerpt? Indirect characterization is used to show that Steve i
Alexandra [31]

Answer:

The answer is B

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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