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liq [111]
2 years ago
5

Line contains points M(1, 3) and N(5, 0). What is the slope of MN?

Mathematics
2 answers:
alexgriva [62]2 years ago
6 0
B. Use the formula m=(Y2-Y1)/(X2-X1). For this problem it would be (0-3)/(5-1)= -3/4.
stellarik [79]2 years ago
3 0
The slope, m, of the line is calculated through the equation,

      m = (y₂ - y₁) / (x₂ - x₁)

where x's are the abscissas of the ordered pair and x's are the ordinates. Substituting the given values to the equation above,

   m = (0 - 3)/(5 - 1) = -3/4

The slope of the line is -3/4 and the answer is letter B. 
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Which best describes thepolynomial 7xy - 15y^3
otez555 [7]

Answer:

Step-by-step explanThis polynomial has three terms. The first one is 4x2, the second is 6x, and the third is 5. The exponent of the first term is 2. The exponent of the second term is 1

8 0
2 years ago
There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. The ratio of the num
ss7ja [257]

Answer:

Step-by-step explanation:

There are 950 students at Hanover High School. The ratio of the number of freshmen to all students is 3:10. This means that the number of freshmen is 3/10 × total number of students.

Number of freshmen = 3/10×950 =285 freshmen

The ratio of the number of sophomore to all students is 1:2. This means that the number of sophomore is 1/2 × total number of students.

Number of sophomore = 1/2×950 =475 sophomore

The ratio of the number of freshmen to sophomore is the number of freshmen/ the number of

sophomore.

It becomes 285/475 = 57/95

6 0
2 years ago
An unloaded truck and trailer, with the driver aboard, weighs 30{,}00030,00030, comma, 000 pounds. When fully loaded, the truck
kari74 [83]

Answer:

1131 pounds.

Step-by-step explanation:

We have been given that an unloaded truck and trailer, with the driver aboard, weighs 30,000 pounds. When fully loaded, the truck holds 26 pallets of cargo, and each of the 18 tires of the fully loaded semi-truck bears approximately 3,300 pounds.

First of all, we will find weight of 18 tires by multiplying 18 by 3,300 as:

\text{Weight of tires of the fully loaded semi-truck}=18\times 3,300

\text{Weight of tires of the fully loaded semi-truck}=59,400

The weight of 26 pallets would be weight of 18 tires minus weight of unloaded truck.

\text{Weight of 26 pallets of cargo}=59,400-30,000

\text{Weight of 26 pallets of cargo}=29,400

Now, we will divide 29,400 by 26 to find average weight of one pallet of cargo.

\text{Average weight of one pallet of cargo}=\frac{29,400}{26}

\text{Average weight of one pallet of cargo}=1130.769230769

\text{Average weight of one pallet of cargo}\approx 1131

Therefore, the average weight of one pallet of cargo is approximately 1131 pounds.

3 0
2 years ago
Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
2 years ago
A semicircular flower bed has a diameter of 3 metres. What is the area of the flower bed?
Yuri [45]

The area of circle is

A_{\text{circle}}=\pi r^2.

Then the area of semicircular region is

A_{\text{semicircular region}}=\dfrac{1}{2} \pi r^2.

If r=3 m, you have

A_{\text{semicircular region}}=\dfrac{1}{2} \pi \cdot 3^2=\dfrac{9\pi}{2}=4.5\pi \approx 14.13 sq. m.

Answer: A_{\text{semicircular region}}=4.5\pi \approx 14.13 sq. m.

3 0
2 years ago
Read 2 more answers
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