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gogolik [260]
2 years ago
15

Amar cycles at a speed of 18km/h.

Mathematics
1 answer:
damaskus [11]2 years ago
7 0

Answer:

<em>The distance between the two villages is 16.5 Km</em>

Step-by-step explanation:

<u>Constant Speed Motion</u>

It's a type of motion in which the distance of an object changes by an equal amount in every equal period of time.

If v is the constant speed, the object travels a distance x in a time t, given by the equation:

x=vt

Amar cycles at v=18 Km/h for t=55 minutes. We need to calculate the distance traveled between the two villages.

Since the speed and the time are given in different units, we convert the time to hours, recalling that 1 hour=60 minute.

t=55 min = 55/60 hours

For the sake of precision, we won't operate the division so far. Compute the distance:

x=18 *55/60=16.5 Km

The distance between the two villages is 16.5 Km

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Please help me. The function g(x) is a transformation of f(x). If g(x) has a y-intercept at 3, which of the following functions
Step2247 [10]
<h3>Answer: D. g(x) = f(x)+4</h3>

The graph shows f(x) to have a y intercept at -1, which is where the diagonal line crosses the y axis. We want the y intercept to move to 3. So we must add 4 to the old y intercept to get the new y intercept.

We do this with every single point on f(x) to get g(x) = f(x)+4. This shifts the graph up 4 units.

8 0
1 year ago
Read 2 more answers
There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet
lutik1710 [3]

There were 340,000 cattle placed on feed

How many of the 340,000 cattle placed on feed were between 700 and 799 pounds?

Given the fraction of total cattle for 700 - 799 pounds is 2/5

Let x be the number of cattle between 700 - 799 pounds

We make a proportion using the fraction

\frac{2}{5} = \frac{x}{340,000}

Cross multiply it and solve for x

340000* 2 = 5x

680000 = 5x

Divide by 5 on both sides

So x= 136,000

There were 136,000 cattle between 700 and 799 pounds

3 0
1 year ago
Read 2 more answers
A. The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.
erastovalidia [21]

Answer:

The average yearly salary of  the architect is <u>$62,000</u> and the lawyer is <u>$100,000</u>.

Step-by-step explanation:

Given:

The average yearly salary of a lawyer is $24 thousand less than twice that of an architect.

Combined, an architect and a lawyer earn $ 210 thousand.

Now, to find the average yearly salary of  an architect and a lawyer.

Let the average yearly salary of  an architect be x.

So, the average yearly salary of  the lawyer = 2x-24,000.

Combined, architect and lawyer earn = \$210,000.

Now, to get the average salary of the architect and lawyer:

x+(2x-24000)=210000

x+2x-24000=210000\\\\3x-24000=210000

<em>Adding both sides 24000 we get:</em>

3x=186,000\\\\Dividing\ both\ sides\ by\ 3\ we\ get:\\\\x=62000.

<u>The average salary of architect = $62,000.</u>

Now, to get the average salary of lawyer by substituting the value of x:

2x-24000\\\\=2(62000)-24000\\\\=124000-24000\\\\=\$100,000.

<u>The average salary of lawyer = $100,000.</u>

Therefore, the average yearly salary of  the architect is $62,000 and the lawyer is $100,000.

4 0
2 years ago
Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

3 0
1 year ago
Evaluate 10m +\dfrac {n^2}410m+ 4 n 2 ​ 10, m, plus, start fraction, n, squared, divided by, 4, end fraction when m=5m=5m, equal
Readme [11.4K]

Answer: 54

Step-by-step explanation:

Given the following expresion provided in the exercise:

10m+\frac{n^2}{4}

You can follow these steps in order to evaluate it when m=5 and n=4:

1. You need to substitute m=5 and n=4 into the given expression:

10(5)+\frac{(4)^2}{4}

2. Now you can solve the mutiplication:

=50+\frac{(4)^2}{4}

3. Since 4^2=4*4, you get:

=50+\frac{16}{4}

4. You must solve the division. Divide the numerator 16 by the denominator 4. Then:

=50+4

5. And finally, you must solve the addition. So, you get this result:

=54

3 0
2 years ago
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