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2 years ago

Amar cycles at a speed of 18km/h.

Mathematics

1 answer:

damaskus [11]2 years ago

7 0

Answer:

The distance between the two villages is 16.5 Km

Step-by-step explanation:

Constant Speed Motion

It's a type of motion in which the distance of an object changes by an equal amount in every equal period of time.

If v is the constant speed, the object travels a distance x in a time t, given by the equation:

x=vt

Amar cycles at v=18 Km/h for t=55 minutes. We need to calculate the distance traveled between the two villages.

Since the speed and the time are given in different units, we convert the time to hours, recalling that 1 hour=60 minute.

t=55 min = 55/60 hours

For the sake of precision, we won't operate the division so far. Compute the distance:

x=18 *55/60=16.5 Km

The distance between the two villages is 16.5 Km

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Step-by-step explanation:

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$L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

Part 2

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

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Replacing we got:

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Part 3

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

Replacing we got:

$T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

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