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1 year ago

Complete the steps to add 32

Mathematics

2 answers:

murzikaleks [220]1 year ago

8 0

Answer:

The result is 47/10 or 4 7/10

Step-by-step explanation:

Let's complete the steps to add 3 2/5 + 1 3/10

1. Write mixed numbers as improper fractions.

17/5 + 13/10

2. Write equivalent fractions with a common denominator.

34/10 + 13/10

3. Add the numerators over the common denominator.

34 + 13 = 47/10

The result is 47/10 or 4 7/10

fgiga [73]1 year ago

4 0

Answer:

Write mixed numbers as improper fractions.

✔ 17/5 + 13/10

2. Write equivalent fractions with a common denominator.

✔ 34/10 + 13/10

3. Add the numerators over the common denominator.

✔ 47/10

Step-by-step explanation:

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2 years ago

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40% of OatyPop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability

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Answer:

the probability is 78.4%

Step-by-step explanation:

there are 3 scenarios

1) gets the price in the 1st box:

the probability is:

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2) gets the price in the 2nd box

P= probability to fail in the fist box * probability to obtain a price

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3) gets the price in the 3rd box

P =probability to fail in the first box * probability to fail in the second box*probability to obtain a price =(6/10)*(6/10)*(4/10)=144/1000 = 14,4%

therefore the probability to obtain a price in 3 or less boxes is:

P = 40%+24%+14.4%= 78.4%

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2 years ago

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The number of hurricanes hitting the coast of Florida annually has a Poisson distribution with a mean of 0.8. Answer the followi

slava [35]

Answer:

a) $P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]$

And we can find the individual probabilities like this:

$P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493$

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

$P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438$

And replacing we got:

$P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474$

b) $P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

Step-by-step explanation:

Let X the random variable that represent the number of hurricanes hitting the coast of Florida annualle. We know that $X \sim Poisson(\lambda=0.8)$

The probability mass function for the random variable is given by:

$f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...$

And f(x)=0 for other case.

For this distribution the expected value is the same parameter $\lambda=0.8$

$E(X)=\mu =\lambda=0.8$

Part a

For this case we want this probability: $P(X>2)$

And for this case we can use the complement rule like this:

$P(X>2)= 1-P(X \leq 2) = 1-[P(X=0)+P(X=1)+P(X=2)]$

And we can find the individual probabilities like this:

$P(X=0) = \frac{e^{-0.8} 0.8^0}{0!}= 0.4493$

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

$P(X=2) = \frac{e^{-0.8} 0.8^2}{2!}= 0.1438$

And replacing we got:

$P(X>2)= 1-P(X \leq 2) = 1-[0.4493+0.3595+0.1438]=0.0474$

Part b

Using the probability mass function we have:

$P(X=1) = \frac{e^{-0.8} 0.8^1}{1!}= 0.3595$

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2 years ago

Given: ΔABC, AC = BC, AB = 3 CD ⊥ AB, CD = √3 Find: AC

valina [46]

Answer:

$\boxed{AC = 2.3}$

Step-by-step explanation:

AD = BD (CD bisects AB means that it divides the line into two equal parts)

So,

AD = BD = AB/2

So,

AD = 3/2

AD = 1.5

Now, Finding AC using Pythagorean Theorem:

$c^2 = a^2+b^2$

Where c is hypotenuse (AC), a is base (AD) and b is perpendicular (CD)

$AC^2= (1.5)^2+(\sqrt{3} )^2$

$AC^2 = 2.25 + 3$

$AC^2 = 5.25$

Taking sqrt on both sides

$AC = 2.3$

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2 years ago

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