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Delvig [45]
2 years ago
8

If 3.0 grams of strontium-90 in a rock sample remained in 1989, approximately how many grams of strontium-90 were present in the

original rock sample in 1933?
Mathematics
1 answer:
kirill [66]2 years ago
5 0

Answer:

<em>11.29 grams </em><em>of strontium-90 were present in the original rock sample in 1933.</em>

Step-by-step explanation:

Strontium has a half-life of 28.8 years. Therefore,

1989 - 1933 = 56 years.

56 / 28.8 = 1.94 half-lives

Thus, the quantity of the radioisotope remaining will double for each half-life elapsed. moving backwards in time.

Therefore, moving backwards in time by 1.94 half-lives, the quantity remaining will double by 1.94 times.

Thus, the amount remaining in 1933 is

3.0 × (1.94)² = <em>11.29 grams</em>

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Suppose that a company claims that its chocolate bars weigh 1.6 ounces on average. It took many large samples, and each time the
Nuetrik [128]

Answer:

The company's chocolate bars weigh 1.6 ounces on average.

Step-by-step explanation:

We are given that  a company claims that its chocolate bars weigh 1.6 ounces on average.

It took many large samples, and each time the mean weight of the sample was within the 95% confidence interval.

95% confidence level means a range of values that you can be 95% certain contains the true mean of the population.

Thus by definition we can say that The company's chocolate bars weigh 1.6 ounces on average.

Hence Option B is correct.

4 0
2 years ago
Read 2 more answers
Isla flipped a coin 30 times. The coin landed heads up 9 times and tails up 21 times.
Debora [2.8K]

Answer:

both are equal

Step-by-step explanation:

there are two side tails and heads so there a 1/2 chance it will land on heads

8 0
2 years ago
Mike has $25.00 to rent paddleboards for himself and a friend for 3 hours. Each paddleboard rental costs $3.75 per hour.use the
Verdich [7]

Mike ($3.75): x

Friends ($3.75): 3x

Mike   +  Friends   ≤  25

3.75(x) + 3.75(3x)  ≤ 25

3.75x  +  11.25x   ≤ 25

                15x      ≤ 25

                 \frac{15x}{15}      ≤  \frac{25}{15}

                  x        ≤ 1\frac{2}{3}

Answer: they can rent the paddleboards for 1 hour 40 minutes

7 0
1 year ago
A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the pr
Gre4nikov [31]

Answer:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:P(-1.5 \leq Z \leq 1.5) = P(zStep-by-step explanation:

A random sample of 36 observations has been drawn from a normal distribution with mean 50 and standard deviation 12. Find the probability that the sample mean is in the interval 47<=X<53. Is the assumption of normality important. Why?

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(50,12)  

Where \mu=50 and \sigma=12

Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

z= \frac{47 -50}{\frac{12}{\sqrt{36}}}=-1.5

z= \frac{53 -50}{\frac{12}{\sqrt{36}}}=1.5

And using a calculator, excel ir the normal standard table we have that:

P(47 \leq \bar X \leq 53) =P(-1.5 \leq Z \leq 1.5)

And we can calculate the probability like this:

P(-1.5 \leq Z \leq 1.5) = P(z

4 0
1 year ago
The sum of two positive integers, x and y, is not more than 40. The difference of the two integers is at least 20. Chaneece choo
oksian1 [2.3K]
<span>Chaneece chooses x as the larger number and uses the inequalities y ≤ 40 – x and y ≤ x – 20 to determine the possible solutions.

</span>y ≤ 40 – x, if x must be between 0 and 10, y must be between 20 and 40 <span>it is true
proof
</span><span>for x=0  and y=10,  y ≤ 40 – x equivalent to 10<40-0=40 it is true
</span>x=10, y=30,   <span>y ≤ 40 – x  equivalent to 30=40-10=30 it is true

the answer is </span><span>A) Yes, Chaneece found the correct solution. </span>
5 0
2 years ago
Read 2 more answers
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