Answer:
D 5 pumpkins, 13 watermelons
Step-by-step explanation:
please give brainiest
0 pumpkins, 0 watermelons
7 pumpkins, 3 watermelons
5 pumpkins, 13 watermelons
5 pumpkins, 5 watermelons
Answer:
89
Step-by-step explanation:He bought 89 items because 20 + 3 is 23, 23 + 12 is 35, 35 + 11 is 46, 46 + 24 is 70, and 70 + 11 is 89.
Answer:
There is no evidence that there is no significant difference between the sample means
Step-by-step explanation:
given that a statistics instructor who teaches a lecture section of 160 students wants to determine whether students have more difficulty with one-tailed hypothesis tests or with two-tailed hypothesis tests. On the next exam, 80 of the students, chosen at random, get a version of the exam with a 10-point question that requires a one-tailed test. The other 80 students get a question that is identical except that it requires a two-tailed test. The one-tailed students average 7.81 points, and their standard deviation is 1.06 points
The two-tailed students average 7.64 points, and their standard deviation is 1.33 points.
Group One tailed X Two tailed Y
Mean 7.8100 7.6400
SD 1.0600 1.3300
SEM 0.1185 0.1487
N 80 80

(Two tailed test)
The mean of One tailed X minus Two tailed Y equals 0.1700
t = 0.8940
df = 158
p value =0.3727
p is greater than alpha 0.05
There is no evidence that there is no significant difference between the sample means
Answer:
Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.
Question 14: The club was making a loss between 11.28 and 4.88 years.
Step-by-step explanation:
Question 13:
The age group y for which the response rate R is 8 microseconds is given by the solution of the equation

We graph this equation and find the solutions to be

Since only positive solutions for y are valid in the real world we take only those.
Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.
Question 14:
The footbal club is making a loss when 
Or

We graph this inequality and find the solutions to be
and 
Since in the real world only positive values for t are valid, we take the the second solution to be true.
Thus the club was making a loss in years 
So since her balance must be at least 500, her ballance cannot reach 500
so 794-500=294
see how many 25's you can fit into 294
we know that 4 25's =100 and 294 is roughly 300
so 4 times 3=12
we minus one of the 25's because 294 is less than 300 so
the innequality is
>means more than
794-25x>500