Answer:
D. -6m²n² + 10m²n + 8mn² - 10mn
Step-by-step explanation:
(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)
Apply the distributive property to remove the parentheses
-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn
Combine like terms together and arrange in standard form
-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn
-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn
-6m²n² + 10m²n + 8mn² - 10mn
Answer:
<x = 31°
Step-by-step explanation:
m<BCA = m<GCJ (vertical angles)
m<BCA = 59° (substitution)
Since line KL is perpendicular to line FG, the angle formed at point B is 90°.
Therefore, m<ABC = 90°
m<BAC + m<ABC + m<BCA = 180° (sum of triangle)
m<BAC + 90° + 59° = 180° (Substitution)
m<BAC + 149° = 180°
m<BAC = 180° - 149°
m<BAC = 31°
<x = <BAC (vertical angles)
m<x = 31° (substitution)
Given inequality: 2y−x ≤ −6
Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied
Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied
Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.
Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.
Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.
Solutions are: (1, -4), (0, -3) , (2, -2)
Number 1 is -23 and number 2 is a
Answer:
c = - 7
Step-by-step explanation:
the standard form of a quadratic equation is
ax² + bx + c = 0 : a ≠ 0
x² + 4x - 7 = 0 is in standard form
By comparison of the coefficients of the terms, c = - 7
