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juin [17]
1 year ago
5

Mr. and Mrs. Smith's children all play different sports. They want to buy a combination of soccer training sets,which each cost

$149, volleyball training set, which each cost $127, and football training sets which each cost $275. Let s represent number of soccer sets, v represent number of volleyball sets and f represent the number of football sets. Which expression represents the total amount of money the Smiths will spend, before sales tax, based on the number of sports sets they buy?
send help please

Mathematics
2 answers:
8090 [49]1 year ago
5 0
C is the answer because a number of children are unknown.
Mumz [18]1 year ago
4 0
He is correct, c I s the answer
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A torch and a battery cost £2.50 altogether. The torch costs £2.00 more than the battery.
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Answer:

\frac{1}{10}

Step-by-step explanation:

Let t represent the cost of the torch and b represent the cost of the battery.

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The torch costs £2.00 more than the battery.

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We substitute the second equation into the first equation to get;

\Rightarrow b+2.00+b=2.50

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We express this as a fraction of the total cost which is £2.50 to get;

\frac{0.25}{2.5}=\frac{1}{10}

8 0
2 years ago
Now imagine that instead of walking along the path 1→2→3→4→1, ann walks 80 meters on a straight line 33∘ north of east starting
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Answer:

Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j} and refer attachment.

Step-by-step explanation:

Let the origin be the point 1 from where Ann start walking.

Ann walks 80 meters on a straight line 33° north of the east starting at point 1 as shown in figure below,

Resolving into the vectors, the vertical component will be 80Sin33° and Horizontal component will be 80Cos33° as shown in figure (2)

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Thus, Anna's walk  as a vector representation is 80\cos 33^{\circ}\hat{i}+80 \sin33^{\circ}\hat{j}

 




7 0
1 year ago
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Given that sum is equal = 210

Lets ( x, y, z ) be the three positive numbers

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take f(x,y,z) = xyz

Q(x,y,z) = 0

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consider the function

F(x,y,z) = f(x,y,z) + λQ(x,y,z)

F = xyz + λ(x+y+z-210)

dF/dx = 0 ⇒ yz + λ(1) = 0 ⇒ λ = -yz   ..............equ(1)

dF/dy = 0 ⇒ xz + λ(1) = 0 ⇒ λ = -xz.................equ(2)

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Now

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MAXIMUM

∛xyz = 70  { when x = y = z = 70}

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Answer:

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Step-by-step explanation:

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