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2 years ago

5

Mr. and Mrs. Smith's children all play different sports. They want to buy a combination of soccer training sets,which each cost

$149, volleyball training set, which each cost $127, and football training sets which each cost $275. Let s represent number of soccer sets, v represent number of volleyball sets and f represent the number of football sets. Which expression represents the total amount of money the Smiths will spend, before sales tax, based on the number of sports sets they buy?
send help please

2 answers:

8090 [49]2 years ago

5 0

C is the answer because a number of children are unknown.

Mumz [18]2 years ago

4 0

He is correct, c I s the answer

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Answer:

$723.66

Step-by-step explanation:

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$\boxed{\green{x = 723.66}}$

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1 year ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

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Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

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2 years ago

The linear equation shown below expresses the revenue of a café based on the number of children and adults who ate there last Tu

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3 children also ate there.

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2 years ago

Read 2 more answers

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Hey!

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2 years ago

Felipe trabaja en una construcción ayuda a cotizar materiales entre ellos cables para diversos propósitos el arquitecto le pidió

Alekssandra [29.7K]

Answer:

a) 0.64mm

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Step-by-step explanation:

Felipe trabaja en una construcción ayuda a cotizar materiales entre ellos cables para diversos propósitos.El arquitecto le pidió cotizar un cable de 16/25 mm de diámetro. en los catálogos disponibles en as tiendas las medidas aparecen expresadas en números decimales como se muestra en la imagen

¿Que debe hacer felipe para saber el diámetro del cable que pidió el arquitecto?

¿que medida en forma de fracción le corresponde al cable que mide 0.28? ¿como lo determinaste? es urgenteeee GRACIAS

a) Dada la dimensión fraccionaria del cable expresada como 16/25 mm, dado que Felipe debe expresar esta fracción en decimal para obtener la medida requerida, dividiremos la expresión usando una división larga como se muestra en el anexo. Desde el archivo adjunto;

16/25 mm = 0,64 mm

b) La medida fraccionaria corresponde al cable que mide 0.28 se expresa como se muestra. Convertir 0,28 a fracción.

0.28 = 28/100 (Tenga en cuenta que dividimos por 100 porque hay dos valores decimales después del punto decimal)

Sobre la simplificación en su término más bajo

28/100 = 4 * 7/4 * 25

28/100 = 4/4 * 7/25

28/100 = 1 * 7/25

28/100 = 7/25

Por lo tanto, la medida fraccionaria que corresponde al cable que mide 0.28 es 7/25.

8 0

2 years ago