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1 year ago

Which graph shows the solution to the system of linear inequalities? x + 3y > 6 y ≥ 2x + 4 PLEASE HELP

Mathematics

2 answers:

Vadim26 [7]1 year ago

4 0

Answer:

Last Graph is the Answer

Step-by-step explanation:

Andrei [34K]1 year ago

3 0

Answer:

x + 3y > 6

Step-by-step explanation:

Find two points that satisfy x + 3y = 6 and draw a DASHED line through them.

It is greater than so shade the section ABOVE that line.

Using the intercept method, the two points I chose are: (0, 2) & (6, 0)

y ≥ 2x + 4

Find two points that satisfy y = 2x + 4 and draw a SOLID line through them.

It is greater than so shade the section ABOVE that line.

The two points I chose are: (0, 4) & (1, 6)

The solution is where the shaded sections overlap.

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In △XYZ, m∠Z = 34, x = 61 cm, and z = 42 cm. Find m∠X. Round your answer to the nearest tenth of a degree.

Elza [17]

M∠X = 54.3°.

Using the Law of Sines, we have:
$\frac{\sin{Z}}{z}=\frac{\sin{X}}{x}
\\
\\\frac{\sin{34}}{42}=\frac{\sin{X}}{61}$

Cross multiplying gives us
61(sin 34) = 42(sin X)

Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X

Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
54.3 = X

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1 year ago

Fiona divided 3x2 + 5x – 3 by 3x +2. The expression represents the remainder over the divisor. x + 1 + What is the value of a?

grigory [225]

x + 1
__________
3x+2 I 3x² +5x -3
3x² +2x
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3x -3
3x+2
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-5 is the remainder

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1 year ago

Read 2 more answers

Stephanie buys a book in a sale for $19.20 . This sale price is after a reduction of 20%. Calculate the original price of the bo

faust18 [17]

Answer:

$96 is the original price of book

Step-by-step explanation:

keep the unknown value as X

(19.2/X)*100 = 20%

19.2/X = 0.2

19.2/0.2 = X

X = 96

6 0

1 year ago

four times the first of three consecutive odd integers is five less than the product of three and the third integer find the int

Andre45 [30]

I don't understand what integer is being asked for. The question is poorly worded.

The three integers are 7, 9, 11.
4 times 7 = 28
and 3 times 11 = 33
and 28 is 5 less than 33.

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1 year ago

Find all x in set of real numbers R Superscript 4 that are mapped into the zero vector by the transformation Bold x maps to Uppe

sukhopar [10]

Answer:

$x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right]$

Step-by-step explanation:

According to the given situation, The computation of all x in a set of a real number is shown below:

First we have to determine the $\bar x$ so that $A \bar x = 0$

$\left[\begin{array}{cccc}1&-3&5&-5\\0&1&-3&5\\2&-4&4&-4\end{array}\right]$

Now the augmented matrix is

$\left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\2&-4&4&-4\ |\ 0\end{array}\right]$

After this, we decrease this to reduce the formation of the row echelon

$R_3 = R_3 -2R_1 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&2&-6&6\ |\ 0\end{array}\right]$

$R_3 = R_3 -2R_2 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&5\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right]$

$R_2 = 4R_2 +5R_3 \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&4&-12&0\ |\ 0\\0&0&0&-4\ |\ 0\end{array}\right]$

$R_2 = \frac{R_2}{4}, R_3 = \frac{R_3}{-4} \rightarrow \left[\begin{array}{cccc}1&-3&5&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&1\ |\ 0\end{array}\right]$

$R_1 = R_1 +3 R_2 \rightarrow \left[\begin{array}{cccc}1&0&-4&-5\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right]$

$R_1 = R_1 +5 R_3 \rightarrow \left[\begin{array}{cccc}1&0&-4&0\ |\ 0\\0&1&-3&0\ |\ 0\\0&0&0&-1\ |\ 0\end{array}\right]$

$= x_1 - 4x_3 = 0\\\\x_1 = 4x_3\\\\x_2 - 3x_3 = 0\\\\ x_2 = 3x_3\\\\x_4 = 0$

$x = \left[\begin{array}{c}4x_3&3x_3&x_3\\0\end{array}\right] \\\\ x_3 = \left[\begin{array}{c}4&3&1\\0\end{array}\right]$

By applying the above matrix, we can easily reach an answer

5 0

1 year ago