Question

An urn contains two red and two green marbles. we pick one marble, record its color, and replace it before picking the second marble. we repeat this procedure a third time. the probability distribution for the number of red marbles is given by number of red marbles 0 1 2 3 probability 1/8 3/8 3/8 1/8 for this distribution, the probability two or more red marbles is given by:

Answer 1

Answer:

$P(X \geq 2) = \frac{1}{2}$

Step-by-step explanation:

Our probability density function indicates that:

$P(X = 0) = \frac{1}{8}$

$P(X = 1) = \frac{3}{8}$

$P(X = 2) = \frac{3}{8}$

$P(X = 3) = \frac{1}{8}$

the probability two or more red marbles is given by

$P(X \geq 2) = P(X = 2) + P(X = 3) = \frac{3}{8} + \frac{1}{8} = \frac{4}{8} = \frac{1}{2}$

Answer 2

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