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eimsori [14]
2 years ago
11

A middle school took all of its 6th grade students on a field trip to see a play. The students filled 660 seats, which was 55% o

f the total number of seats in the theater. How many total seats were in the theater?
Mathematics
1 answer:
Elan Coil [88]2 years ago
7 0

Answer:

1200 seats

Step-by-step explanation:

<u>  x  </u>  =  <u> 660 </u>

100        55

55x = 66,000

x = 1200

You might be interested in
Find the area of the shaded portion in the equilateral triangle with sides 6. Show all work for full credit. (Hint: Assume that
Vadim26 [7]
So... if you notice the picture below

each circle, has their central angle at the vertex of the triangle
that simply means, 3 circles with a radius of 3, overlapping the triangle

now, the area in the middle, the shaded one, will be, the whole area of the triangle MINUS those 3 circle sectors

hmmmm each sector has 60°, that means, all three of them will then be 60+60+60 or 180°, so the area of those three sectors, can be combined into a 180° sector, well, hell, 180° is really half a circle

so.... the area of those three sectors of 60° each, all three combined, is the same area of half a circle with a radius of 3

so    \bf \textit{area of an equilateral triangle}\\\\&#10;A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}\\\\&#10;-----------------------------\\\\&#10;\textit{area of a circle}\\\\&#10;A=\pi r^2\qquad r=radius\\\\&#10;\textit{area of half a circle}\\\\&#10;A=\cfrac{\pi r^2}{2}\\\\&#10;-----------------------------\\\\

\bf \textit{now, let us use the side of 6, and radius of 3}&#10;\\\\\\&#10;&#10;\begin{array}{clclll}&#10;\cfrac{6^2\sqrt{3}}{4}&-&\cfrac{\pi 3^2}{2}\\&#10;\uparrow &&\uparrow \\&#10;triangle's&&semi-circle's&#10;\end{array}\impliedby \textit{area of shaded area}\\\\&#10;-----------------------------\\\\&#10;\boxed{\cfrac{36\sqrt{3}}{4}-\cfrac{9\pi }{2}}

you can, add the fractions if you want, or leave them like that, or get their difference by using their decimal format

8 0
2 years ago
Read 2 more answers
Question: 2. Musah Stands At The Centre Of A Rectangular Field. He First Takes 50 Steps North, Then 25 Steps West And Finally 50
Iteru [2.4K]

Answer:

60.36 steps West from centre

85.36 steps North from centre

Step-by-step explanation:

<em>Refer to attached</em>

Musah start point and movement is captured in the picture.

  • 1. He moves 50 steps to North,
  • 2. Then 25 steps to West,
  • 3. Then 50 steps on a bearing of 315°. We now North is measured 0°

or 360°, so bearing of 315° is same as North-West 45°.

<em />

<em>Note. According to Pythagorean theorem, 45° right triangle with hypotenuse of a has legs equal to a/√2.</em>

<u />

<u>How far West Is Musah's final point from the centre?</u>

  • 25 + 50/√2 ≈ 60.36 steps

<u>How far North Is Musah's final point from the centre?</u>

  • 50 + 50/√2 ≈ 85.36 steps

7 0
1 year ago
The function H(t) = −16t2 + 48t + 12 shows the height H(t), in feet, of a cannon ball after t seconds. A second cannon ball move
Thepotemich [5.8K]
Part A:
To determine the values of the times to which the height of the two cannon balls are the same, we equate the given functions.
    H(t) = g(t)
Substitute the expressions for each.
  -16t² + 48t + 12 = 10 + 15.2t

Transpose all the terms to the left-hand side of the equation.
 -16t² + (48 - 15.2)t + (12 - 10) = 0

Simplifying,
   -16t² + 32.8t + 2 = 0

The values of t from the equation are 2.11 seconds and -0.059 seconds

Part B:
In the context of the problem, only 2.11 seconds is acceptable. This is because the second value of t which is equal to -0.059 seconds is not possible since there is no negative value for time. 
8 0
2 years ago
Jolyn, a golfer, claims that her drive distance is not equal to 222 meters, on average. Several of her friends do not believe he
Troyanec [42]

Answer:

0.29

Step-by-step explanation:

z-score is given by the formula:

z=(μ-M)/σ where

  • μ is the hypothesis drive distance, which is 222
  • M is the mean sample drive distance
  • σ is the standard deviation of the sample drive distance

Therefore

z=(222-218)/14≈0.29

3 0
2 years ago
In order to estimate the average electricity usage per month, a sample of 125 residential customers were selected, and the month
mr_godi [17]

Answer:

[895.05; 940.81]kWh

Step-by-step explanation:

Hello!

Be X: monthly electricity usage by a residential customer

X~N

σ²: 12100KWh²

To estimate the population mean using a 98% CI you have to use the following formula

[X[bar]±Z_{1-\alpha /2} * \frac{Sigma}{\sqrt{n} }]

1-α: 0.98

α0.02

α/2: 0.01

1-α/2:0.99

Z_{1-\alpha /2}= Z_{0.99}= 2.326

n= 125

X[bar]= ∑X/n= 228565/125= 917.93

[917.93±2.326 * \frac{110}{\sqrt{125} }]

[895.05; 940.81]

Using a 98% confidence level you'd expect that the interval [895.05; 940.81]kWh will include the average monthly electricity usage of residential customers.

I hope this helps!

Raw data:

Electric Usage

765

1139

714

687

1027

1109

749

799

911

631

975

717

1232

806

637

894

856

896

1272

1224

621

606

898

723

817

746

933

595

851

1027

770

685

750

1198

975

678

1050

886

826

1176

583

841

1188

692

733

791

584

1163

593

1234

603

1044

1233

1178

598

904

778

693

590

845

893

1028

975

788

1240

1253

854

1185

1164

741

1058

1053

795

1198

1240

1140

959

938

1008

1035

1085

1100

680

1006

977

1042

1252

943

1165

1014

912

791

612

935

864

953

667

1005

1063

1095

1086

810

1032

970

1099

1229

892

1074

579

754

1007

1116

583

763

1231

966

962

1132

738

1033

697

891

840

725

1031

7 0
2 years ago
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