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irina [24]
2 years ago
12

Choose the word phrase (greater than, less than, or equal to) to make the statements true.

Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
3 0

Answer:

Five pencils and two marches are worth greater than thirty paper clips.

Step-by-step explanation:

Let 'x' be paper clip.

Let 'y' be a match

and let 'z' be a pencil.

Now, let's write each statement as an equation:

Each paper clip can be traded for three matches:

x = 3y

Each pencil can be traded for six paper clips:

z = 6x

Now, five pencils equals 30 paper clips and two matches equals two thirds papel clips.

Therefore, we can say that Five pencils and two matches equals 30.66 matches. Therefore, five pencils and two marches are worth greater than thirty paper clips.

sergeinik [125]2 years ago
3 0

Answer:

less than

Step-by-step explanation:

Let x be the worth of a match.

Each paper clip can be traded for three matches. It means the worth of a paper clip is 3 times of the worth of a match.

Worth of a paper = 3x

Each pencil can be traded for six paper clips. It means the worth of a pencil is 6 times of the worth of a paper clip.

Worth of a pencil = 6(3x) =18x

The worth of a match, a paper and pencil are x, 3x and 18x respectively.

Worth of Twelve matches = 12 × x = 12x

Worth of two pencils and one paper clip = 2(18x) + 1(3x) = 39x

It is clear that

12x

because,

12

Therefore, the twelve matches are worth  less than two pencils and one paper clip.

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10. If PQRS is a parallelogram, then P - R is:<br>(a) 20<br>(b) 30<br>(c) 90<br>(d) 0​
statuscvo [17]

Answer:

d) 0

Step-by-step explanation:

P -R = 0

Because in parallelogram, opposite angles are equal.

4 0
2 years ago
A clock is showing the time as exactly 3:00 p.m. and 25 s. Because a full minute has not passed since 3:00, the hour hand is poi
Grace [21]
I had to read this a couple of times to see this was not about time, but is a right triangle problem. If the hour hand is at three, let us consider that a leg of a right triangle, we will consider the hypotenuse as the second hand.
Sketch the picture. 

The hypotenuse is 9 cm. the angle is found by: 

the (hour hand) is pointing directly at the 12. I expect you mean the minute hand. The angle between the minute hand and the second hand is 25/60*360 = 150 which make the angle between the hour hand and the second hand. 150 -90 =60 

so the second hand and the hour hand gives us a right triangle, with a 60 degree angle and a hyp. of 9 cm. 

cos 60 = x/9 

9 cos 60 =x 
<span>
x = 4.5 cm

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
3 0
2 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
Lilit [14]

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

If\ a=b\ then\ a*c=b*c

In this case, the equation that Jada had is the folllowing:

-\frac{4}{9}=\frac{x}{108}

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by -\frac{4}{9}<em>  </em>and the right side by -\frac{9}{4}.

Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.

3 0
2 years ago
Read 2 more answers
Elizabeth lives in San Francisco and works in Mountain View. In the morning, she has 333 transportation options (take a bus, a c
matrenka [14]
All transportation (bus, cab, train) are all similarly likely to be selected, and 1 of them must be selected at morning and evening, so we get: P (bus) = P (cab) = P (train) = 1/3. We also have P(no cab in evening) = P(no cab at morning) = 2/3 
Now, P(using cab exactly once) = P(cab at morning and no cab in the evening) + P(no cab at morning and cab in the evening)
= P(cab, no cab) + P(no cab, cab) 
= 1/3 * 2/3 + 2/3 * 1/3 
= 2/9 + 2/9 
= 4/9 
Probability that Elizabeth uses a cab only once is 4/9.
7 0
2 years ago
Read 2 more answers
 consider the figures below which of the following statements are true given angle S is congruent to angle J and angle N is con
Vsevolod [243]

Answer:

A C D E F

Step-by-step explanation:

Might be wrong

7 0
2 years ago
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