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pishuonlain [190]
2 years ago
12

The price of a recipe-book was reduced from $24.50 to$17.95. If p represents the percent decrease in price of the book, which pr

oportion can be used to calculate p? please help :)
Mathematics
1 answer:
LuckyWell [14K]2 years ago
4 0

Answer:

The required proportion is \frac{p}{100}=\frac{24.50-17.95}{24.50}.

Step-by-step explanation:

Consider the provided information.

The price of a recipe-book was reduced from $24.50 to$17.95.

The original price is 24.50

Reduced price is 17.95.

Let p represents the percent decrease in price of the book.

\text{Percent decrease}=\frac{\text{Original price-Reduced price}}{\text{Original price}}\times 100

Now substitute the respective values in the above formula.

p=\frac{24.50-17.95}{24.50}\times 100

\frac{p}{100}=\frac{24.50-17.95}{24.50}

Hence, the required proportion is \frac{p}{100}=\frac{24.50-17.95}{24.50}.

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A lock has 5 buttons. The lock is opened by pushing two buttons simultaneously and then by pushing one button alone. How many co
Pavel [41]

We first must calculate how many ways 2 oblects can be chosen from 5.

combinations = 5! / 2! * (5-2)!

combinations = 5*4 / 2

combinations = 10


There are 10 ways to choose the 2 buttons and 5 ways to choose the final butto so there are 10 * 5 = 50 different ways.


Source

1728.com/combinat.htm




7 0
1 year ago
The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
Solve the following addition and subtraction problems. a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam b. 5 sq.km 95 ha 8,994 sq.m + 11 sq.
kipiarov [429]
As a general rule to solve the problem we are going to transform all values to the lower unit.  
a. 3 km 9 hm 9 dam 19 m + 7 km 7 dam
  3,000 m 900 m 90 m 19 m + 7,000 m 70 m = 4,009 + 7,070 = 11,079 m 
  b. 5 sq.km 95 ha 8,994 sq.m + 11 sq. km. 11 ha 9,010 sq. m.
  5,000,000 sq m 95,0000 sq m 8,994 sq m + 11,000,000 sq m 110,000 sq
9,010 sq m
  5,103,994 sq m + 11,119,010 sq m = 16,223,004 sq m 
 c. 44 m – 5 dm
  44 m - 0.5 m = 43.5 m 
 d. 73 km 47 hm 2 dam - 11 km 55 hm

  73,000 m 4,700 m 20 m - 11,000 m 5,500 m 
77,720 m - 16,500 m = 61,220 m
5 0
2 years ago
Sarah received \$55$55dollar sign, 55 for her birthday. She used some of that money to buy 333 shirts priced at mmm dollars each
satela [25.4K]

Answer:

$(55-3m) is the amount of money she has left

Step-by-step explanation:

In this question, we are asked to give an expression to represent how much money was left after Sarah had bought some certain stuffs at some prices using the money she received at her birthday.

Firstly, we identify that the total amount of money she has to spend is $55.

Now let’s project her total spendings. She bought 3 shirts with each shirt costing $m.

The total amount spent on the shirts is thus; 3 * $m = $3m

The amount of money she has left is the difference.

Mathematically, this is equal to $55 - $3m

4 0
1 year ago
Read 2 more answers
At the Last Chance Filling Station, gas costs $1.60 a gallon. Trevor paid $32.00 to fill his tank. How many gallons of gas did h
Mariana [72]

Answer:

1.60x=32.00

Step-by-step explanation:

Since you do not how much gallons of gas he bought you would use the variable x.

8 0
1 year ago
Read 2 more answers
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