In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.
In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.
What would the graphs look like?
In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.
In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.
Answer:
i dont know about the other parts but part A is 19
Step-by-step explanation:
She got a 20% discount (or 80% discount). (Work shown for 80%).
First you have to find out how much Mandy paid. So from 15000 you will subtract 3000. 15000-3000=12000.
Next you need to set up your equation.

. You then have to cross multiply. So 100 times 12000, 100*12000=1200000. And 15000 times x is 15000x. Finally you divide both sides by 15000. And 1200000 divided by 15000 is 80. X=80
Answer:
The answer is C
Step-by-step explanation:
got it right on edge