Draw a bar model that shows how the number of hours in March compares with the number of hours in February of this year.

Mathematics

2 answers:

gogolik [260]2 years ago

8 0

Okay so first we need to find how many days are in March and February. March has 31 days and because this year was a leap year February has 29 days.

The next step is to convert days to hours.
March: 31x24=744
February: 29x24=696

Now its time to graph

Sav [38]2 years ago

8 0

Answer:

Firstly we calculate the number of hours of both months.

This year is not a Leap year. So, the number of days of February is 28

and the number of days of March is 31

So, Number of hours February has 28 × 24 = 672 hours

and, Number of hours March has 31 × 24 = 744 hours

The bar graph is the best visual representation when we have categorical data. It is drawn by using a rectangular bar where the length of the bar represents height or frequency.

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You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl

gtnhenbr [62]

Answer:

maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

Step-by-step explanation:

We know that area of circle is given by

$A=\pi \times (radius)^{2}$

For circle with radius 'r' we have

$A_{1}=\pi \times (r)^{2}$

For circle with radius 'R' we have

$A_{2}=\pi \times (R)^{2}$

Now according to given condition we have

$A_{1}-A_{2}\leq \frac{5}{\pi }$

$\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}$