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2 years ago

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Two new cars were purchased from Frank’s Auto Yard. Car A’s value n years after its purchase is found using the function P(n) =

13,500(0.83)n. Car B’s value in different years is shown in the table below.

1 answer:

Elis [28]2 years ago

3 0

Answer:

7 percent.

Step-by-step explanation:

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A local project being analyzed by PERT has 42 activities, 13 of which are on the critical path. If the estimated time along the

ryzh [129]

Answer:

the probability that the project will be completed in 95 days or less, P(x ≤ 95) = 0.023

Step-by-step explanation:

This is a normal probability distribution question.

We'll need to standardize the 95 days to solve this.

The standardized score is the value minus the mean then divided by the standard deviation.

z = (x - xbar)/σ

x = 95 days

xbar = mean = 105 days

σ = standard deviation = √(variance) = √25 = 5

z = (95 - 105)/5 = - 2

To determine the probability that the project will be completed in 95 days or less, P(x ≤ 95) = P(z ≤ (-2))

We'll use data from the normal probability table for these probabilities

P(x ≤ 95) = P(z ≤ (-2)) = 0.02275 = 0.023

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2 years ago

Mrs. Blackwell gives each of her students two pencils. How many pencils did she hand out?

MakcuM [25]

<span>no está en mi equipo lo siento</span>

6 0

1 year ago

Read 2 more answers

Which is a stretch of an exponential growth function? f(x) = Two-thirds (two-thirds) Superscript x f(x) = Three-halves (two-thir

Arte-miy333 [17]

Answer:

f(x) = Three-halves (three-halves) Superscript x

f(x) = Two-thirds (three-halves) Superscript x

Step-by-step explanation:

Since, a function in the form of $f(x) = ab^x$

Where, a and b are any constant,

is called exponential function,

There are two types of exponential function,

Growth function : If b > 1,

Decay function : if 0 < b < 1,

Since, In

$f(x) =\frac{2}{3}(\frac{2}{3})^x$

$\frac{2}{3} < 1$

Thus, it is a decay function.

in $f(x) =\frac{3}{2}(\frac{2}{3})^x$

$\frac{2}{3} < 1$

Thus, it is a decay function.

in $f(x) =\frac{3}{2}(\frac{3}{2})^x$

$\frac{3}{2} > 1$

Thus, it is a growth function.

in $f(x) =\frac{2}{3}(\frac{3}{2})^x$

$\frac{3}{2} > 1$

Thus, it is a growth function.

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2 years ago

Read 2 more answers

Notice that the alternative hypothesis is a two-tailed test. Suppose ttest_ind method from scipy module is used to perform the t

Korvikt [17]

Answer:

The <em>p</em>-value of the test is 0.0512.

Step-by-step explanation:

The <em>p</em>-value of a test is well-defined as per the probability, [under the null hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.

In this case the output of the t-test_ind method from scipy module is provided as follows:

Output = (-1.99, 0.0512)

The first value within the parentheses is the test statistic value.

So the test statistic value is, -1.99.

And the second value within the parentheses is the <em>p</em>-value of the test.

So the <em>p</em>-value of the test is 0.0512.

6 0

2 years ago

James wants to invest $12,000. He can invest the money at 7.2% simple interest for 30 yr or he can invest at 6.8% with interest

Sever21 [200]

Over time, compound interest at any rate will outperform simple interest. When the rates are nearly equal to start with, compound interest will be greater in very short order. Here, it takes less than 1 year for compound interest to give a larger account balance.

In 30 years, the simple interest will be

... I = P·r·t = 12,000·0.07·30 = 25,200

In 30 years, the compound interest will be

... I = P·(e^(rt) -1) = 12,000·(e^(.068·30) -1) ≈ 80,287.31

_____

6.8% compounded continuously results in more total interest

4 0

1 year ago