The answer to the problem is y^12
When putting data into a class for this case, 0.350 - 0.359, they should be within the class boundaries. The class boundaries are 0.3495 and 0.3595. So, the data that will go into that class are 0.356 and 0.358. The record 0.349 is not included since it is below 0.3495. Therefore, there are only two values in the class.
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9(millions), 9(hundred-thousands)9(ten-thousands)9(thousands), 9(hundreds)9(tens)9(ones).
The vertex form of the function gives the vertex as (-6,48). The vertex of f(x)=x^2 is (0,0) so from this information, the vertex is moved LEFT 6 and UP 48. This cancels out two options. The coefficient -3 tells us that the graph is flipped or reflected over the x-axis (negative sign flips graph) and that all y-values will be 3 times as large. Larger y-values for the same x inputs makes the graph narrower.
Answer:
15x < 200; x < 13.33; the maximum price for a pair of shorts
Step-by-step explanation:
1. Set up the inequality
Let x = price of a pair of shorts. Then
15x = price of shorts for the team
You have one condition:
15x < 200
2. Solve the inequality
3. Meaning of solution
The solution represents the maximum price the coach can pay for a pair of shorts.
If the coach pays $13.33 per pair, the total cost for the team will be $199.95, and the condition is satisfied.
