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Artyom0805 [142]
1 year ago
6

Rewrite in polar form: x=12. I have r=12 sec theta

Mathematics
2 answers:
Wittaler [7]1 year ago
7 0

Answer:

C. r=12Secθ

Step-by-step explanation:

romanna [79]1 year ago
3 0
To solve this problem you must apply the proccedure shown below:
 1. You have to r<span>ewrite x=12 in polar form. Then, you have:
 12=rCos</span><span>θ
 2. Then, you must solve for r, as following:
 r=12/Cos</span><span>θ
</span> 3. You have that 1/Cosθ=Sec<span>θ, therefore:
</span> r=12(1/Cos<span>θ)
</span> r=12Sec<span>θ
</span> Therefore, as you can see, the answer is: r=12Secθ<span>
 </span>
You might be interested in
Suppose you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by model
Ann [662]

Answer:

(1) The degrees of freedom for unequal variance test is (14, 11).

(2) The decision rule for the 0.01 significance level is;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The value of the test statistic is 0.3796.

Step-by-step explanation:

We are given that you are an expert on the fashion industry and wish to gather information to compare the amount earned per month by models featuring Liz Claiborne's attire with those of Calvin Klein.

The following is the amount ($000) earned per month by a sample of 15 Claiborne models;

$3.5, $5.1, $5.2, $3.6, $5.0, $3.4, $5.3, $6.5, $4.8, $6.3, $5.8, $4.5, $6.3, $4.9, $4.2 .

The following is the amount ($000) earned by a sample of 12 Klein models;

$4.1, $2.5, $1.2, $3.5, $5.1, $2.3, $6.1, $1.2, $1.5, $1.3, $1.8, $2.1.

(1) As we know that for the unequal variance test, we use F-test. The degrees of freedom for the F-test is given by;

\text{F}_(_n__1-1, n_2-1_)

Here, n_1 = sample of 15 Claiborne models

         n_2 = sample of 12 Klein models

So, the degrees of freedom = (n_1-1, n_2-1) = (15 - 1, 12 - 1) = (14, 11)

(2) The decision rule for 0.01 significance level is given by;

  • If the value of our test statistics is less than the critical values of F at 0.01 level of significance, then we have insufficient evidence to reject our null hypothesis.      
  • If the value of our test statistics is more than the critical values of F at 0.01 level of significance, then we have sufficient evidence to reject our null hypothesis.  

(3) The test statistics that will be used here is F-test which is given by;

                          T.S. = \frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }  ~ \text{F}_(_n__1-1, n_2-1_)

where, s_1^{2} = sample variance of the Claiborne models data = \frac{\sum (X_i-\bar X)^{2} }{n_1-1} = 1.007

s_2^{2} = sample variance of the Klein models data = \frac{\sum (X_i-\bar X)^{2} }{n_2-1} = 2.653    

So, the test statistics =  \frac{1.007}{2.653 } \times 1  ~ \text{F}_(_1_4,_1_1_)

                                   = 0.3796

Hence, the value of the test statistic is 0.3796.

3 0
1 year ago
Natasha uses 2.5 feet of twine to tie campfire wood into bundles. The proportional relationship between the number of bundles, x
Blababa [14]

I am not sure but I think it represent the middle coordinate

4 0
1 year ago
Gabriel is saving money by mowing lawns on the weekends. Last month, he saved $150. This month, saved 20% more than he saved las
Katyanochek1 [597]

Answer:

180

Step-by-step explanation:

so last month he saved 150 right first you find 20% of 150. that is 30. you add 150 and 30 and get 180.

3 0
2 years ago
Read 2 more answers
A started some business with RS 26,000. After 3 month B joined him with Rs. 16,000. After some more time C joined them with Rs.
viktelen [127]

Answer:

3  months

Step-by-step explanation:

<h2><u>A:</u></h2>

We know that the total investment period is 1 year, then since A started, A invested Rs 26,000.

<u>Now, since A has been working for 12 months, this is where the effective investment comes in:</u>

A effective investment = Rs 312,000

<h2><u>B:</u></h2>

<u>Then after 3 months, B joined, so:</u>

12 months - 3 months = 9 months in work

B overall invested = Rs 16,000

<u>Since B only worked nine months, we use that to find effective investment:</u>

B effective investment = Rs 144,000

<h2>C:</h2>

<u>C joined x months since B joined in:</u>

<u>We don't know how much C worked for, but we know that C joined after B:</u>

C investment period = 9 months - x certain amount of months

We know that C's investment is Rs 25,000

<u>Find effective investment:</u>

<u>Rs 25,000 * ( 9 - x ) = Rs 225,000 - 25,000x then to find the total investment:</u>

<u></u>

<u>Add all effective investment:</u>

Rs 312,000 + Rs 144,000 + Rs 225,000 - 25,000x

= Rs 681000 - 25,000x

We now know that C's investment is 225,000 - 25,000x

<u>Find profit share:</u> 225,000 - 25,000x

==> Rs 3,825

<u>The total profit:</u>

Rs 15,453

<u>To get our final answer, we must do this operation:</u>

<u>C investment divided by Total Investment = C's profit and total profit:</u>

( Rs 225,000 - 25,000x) ÷ ( Rs 681,000 - 25,000x ) = Rs 3,825 / Rs 15,453

25 ( Rs 9,000 - 1,000x)/(Rs 681,000 - 25,000x)  = (153 * 25) /(153 * 101)

( Rs 9,000 - 1,000x ) ÷ ( Rs 681,000 - 25,000x ) = 1 / 101

Rs 909,000 - 101,000x = Rs 681,000 - 25,000x

Rs 228,000 = 76,000x

Rs 228 = 76x

x = 3

8 0
2 years ago
Which is the additive inverse of the complex number -8+3i?
lawyer [7]
The additive inverse of a complex z is a complex number -z, so that

\mathsf{z+(-z)=-z+z=0+0i=0}


Finding -z:

\mathsf{z=-8+3i}\\\\\\ \mathsf{z+(-z)=0+0i}\\\\\ \mathsf{-8+3i+(-z)=0+0i}\\\\ \mathsf{-z=0+0i+8-3i}\\\\ \mathsf{-z=(0+8)+(0i-3i)}\\\\ \boxed{\begin{array}{c}\mathsf{-z=8-3i} \end{array}}\qquad\checkmark


If you're having problems understanding this answer, try seeing it through your browser: <span>brainly.com/question/2159647


</span>I hope this helps.


Tags: <em>complex number additive inverse opposite algebra</em>

3 0
2 years ago
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