Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
Answer:
Step-by-step explanation:
- The cross section of a sphere is a circle with area
, where radius is given as 4 - The cross section of the cube is a square with area
, where a is side length of square
The circle area = the square area. Thus we have:
We know that
point A(1,1) C(3,5)
point D(-2,-4) F(0,0)
step 1
find the slope FD
m=(y2-y1)/(x2-x1)------> m=(0+4)/(0+2)----> m=4/2----> m=2
step 2
find the slope AC
m=(y2-y1)/(x2-x1)------> m=(5-1)/(3-1)----> m=4/2-----> m=2
mAC=mFD
the answer is
the slope FD is 2
Answer:
2.5
Step-by-step explanation:
Simplifying –8.3 + 9.2 – 4.4 + 3.7.
Identify and explain any errors in his work or in his reasoning
Original problem 1. −8.3 + 9.2 + 4.4 + 3.7
Additive inverse 2. −8.3 + 4.4 + 9.2 + 3.7 (error, not additive inverse; +3-3=0)
Commutative property 3. −8.3 + (4.4 + 9.2 + 3.7)
Associative property 4. −8.3 + 17.3
Simplify 5. 9
