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1 year ago

11

To make purple paint, Mya mixed 2/5 cup of red paint with 5/8 cup of blue paint. She wants to make a larger batch of the purple

paint. How much red paint is needed to mix one cup of blue paint?
Please help!!!

1 answer:

Hitman42 [59]1 year ago

8 0

She should use 5/8 cups i think

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3) You find a jar of quarters on the sidewalk and decide to start collecting them to cash in at the end of the school year.

soldier1979 [14.2K]

Answer:

I dont rally know

Step-by-step explanation:

try it yourself

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1 year ago

Omar and Caleb each had a repair made on their cars. The initial cost of each repair is $1,000. Omar and Caleb each have two cou

scoundrel [369]

Answer:

854

Step-by-step explanation:

1000/15=66

1000-66-80=854

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1 year ago

A television camera at ground level is filming the lift-off of a space shuttle at a point 750 meters from the launch pad. Let θ

ss7ja [257]

750 * x =

0^1 = 0 =

750 x 0 = 750

A: 750 meters

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1 year ago

in any given year a factory has a 10% probability of having a serious accident. about every how many years might the factory exp

Likurg_2 [28]

Years for one serious accident is 10 year

<u>Given:</u>

Probability of having a serious accident = 10% every year

P(serious accident) = 0.1

Number of years = n

<u>Computation:</u>

Years for one serious accident = 1 / Probability of having a serious accident

Years for one serious accident = 1 / P(serious accident)

Years for one serious accident = 1 / 0.1

Years for one serious accident = 10 year

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1 year ago

A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th

Kitty [74]

Answer:

a

The 90% confidence interval is $52561.13 < \mu < 57540.8$

b

Confidence interval for the population men between <u>$52561.13</u> up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

The sample size is $n = 25$

The sample mean is $\= x = \$ 55,051$

The standard deviation is $\sigma = \$ 7,568$

Given that the confidence level is 90% then the level of confidence is mathematically represented as

$\alpha = 100 -90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table the values is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{ 7568}{ \sqrt{ 25} }$

$E = 2489.9$

The 90% confidence interval is mathematically evaluated as

$\= x -E < \mu < \= x +E$

substituting values

$55051 - 2489.8 < \mu < 55051 + 2489.8$

$52561.13 < \mu < 57540.8$

6 0

1 year ago