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Dominik [7]
2 years ago
11

To make purple paint, Mya mixed 2/5 cup of red paint with 5/8 cup of blue paint. She wants to make a larger batch of the purple

paint. How much red paint is needed to mix one cup of blue paint?
Please help!!!
Mathematics
1 answer:
Hitman42 [59]2 years ago
8 0
She should use 5/8 cups i think 
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If g(x)=4x^2-16 were shifted 5 units to the right and 2 down, what would the new equation be?
Eduardwww [97]
Try this, pls:
When any line on graph is moved to the right, for 'x' must be '-'.
When one is moved down, for 'y' must be '-'.
Finaly: y=4(x-5)²-18.
Answer: A.
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2 years ago
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Miguel's family drove 357 miles on their weekend trip. Their car's average gas mileage was 25.5 miles per gallon, How
mina [271]

Answer: d 140

Step-by-step explanation:

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2 years ago
Researchers are studying populations of two squirrels, the eastern gray and the western gray. For the eastern gray squirrel, abo
Tresset [83]

Answer:

p₁  -  p₂  = ( -0,28 . 0 )

Step-by-step explanation:

Eastern gray squirrel

Sample size    n₁  = 60

p₁  =  22 %        p₁  = 0,22       then     q₁  = 1 - 0,22      q₁ = 0,88

Western gray squirrel

Sample size  n₂  =  120

p₂ = 36%     p₂ = 0,36     Then    q₂  =  1  - 0,36     q₂  =  0,64

p (s)  = ( p₁ - p₂ ) /√ (p₁*q₁ ) / n₁   +  (p₂*q₂/ n₂)

p(s)  = ( 0,22 -  0,36 ) /√ (0,22*0,88)/60  +  ( 0,36*0,64)/120

p(s)  =  -0,14 /0,071

p(s) = - 1,9718

Then

CI = (  p₁ - p₂ ) ± p(s) *EED

EED =  /√ (p₁*q₁ ) / n₁   +  (p₂*q₂/ n₂)   = 0,071

CI = (  - 0,14  ±  1,9718 * 0,071 )

CI =  ( - 0,14  ±  0,14 )

CI =  ( - 0,28 ;  0 )

we will find with 95% of confidence the mean of the sampling distribution of the difference in sample proportion in the interval  ( -0,28 , 0 )

p₁  -  p₂  = ( -0,28 . 0 )

6 0
2 years ago
Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]        

Width for n = 64:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision

5 0
2 years ago
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In expanded notation, the hexadecimal 74AF16 is (7*4096) + (4*256) + (A*16) + (F*1). When converting from hexadecimal to decimal
Feliz [49]

Answer:

F is assigned the value of 15

74AF_{16} = 29871_{10}

Step-by-step explanation:

Hexadecimal number system is base 16 and it contain the following numbers:

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F

A has a value of 10

B has a value of 11

C has a value of 12

D has a value of 13

E has a value of 14

F has a value of 15

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(7*4096) + (4*256) + (A * 16) + (F *1)\\= (7*4096) + (4*256) + (10 * 16) + (15 *1)\\= 28672 + 1024 + 160 + 15\\= 29871

6 0
2 years ago
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