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gavmur [86]
2 years ago
15

If k(x) = 5x – 6, which expression is equivalent to (k + k)(4)?. . 5(4 + 4) – 6. 5(5(4) – 6) – 6. 54 – 6 + 54 – 6. 5(4) – 6 + 5(

4) – 6
Mathematics
2 answers:
Dmitrij [34]2 years ago
6 0
K(x) = 5x-6
(k+k)(x) = k(x) + k(x) = 5x-6 +5x-6
just plug in x = 4,
(k+k)(4) = 5(4) -6 + 5(4) -6
thats your answer, the last option.
Ghella [55]2 years ago
5 0

Answer:

d

Step-by-step explanation:

100%

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What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp
finlep [7]

Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!

4 0
1 year ago
A small ferryboat is 4.00 m wide and 6.00 m long. When a loaded truck pulls onto it, the boat sinks an additional 4.00 cm into t
Svet_ta [14]

Answer:

F_w=9408\ N

Weight of the truck=9408 N

Step-by-step explanation:

Boat is experiencing the buoyant force as it is in the water and is sinking

According to the force balance in y direction. As both is floating, two forces balance each other:

F_b-F_w=0

where:

F_b is the buoyant force

F_w is the weight=mg

F_b=F_w        Eq (1)

Buoyant force is equal to the mass of water displaced * gravitational acceleration.

F_b=m_{water\ displaced}*g\\F_b=\rho Vg\\

Taking density of water to be 1000 Kg/m^3

F_b=1000*(6*4*4*10^{-2})*9.8\\F_b=9408 N

From Eq(1):

F_w=9408\ N

Weight of the truck=9408 N

6 0
2 years ago
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random sample of
nikitadnepr [17]

Answer:

a) Reject H₀

b) [0.31; 3.35]

Step-by-step explanation:

Hello!

a) The objective of this example is to compare if the population means of the production rate of the assembly lines A, B and C. To do so the data of the production of each line were recorded and an ANOVA was run using it.

The study variable is:

Y: Production rate of an assembly line.

Assuming that the study variable has a normal distribution for each population, the observations are independent and the population variances are equal, you can apply a parametric ANOVA with the hypothesis:

H₀ μ₁= μ₂= μ₃

H₁: At least one of the population means is different from the others

Where:

Population 1: line A

Population 2: line B

Population 3: line C

α: 0.01

This test is always one-tailed to the right. The statistic is the Snedecor's F, constructed as the MSTr divided by the MSEr if the value of the statistic is big, this means that there is a greater variance due to the treatments than to the error, this means that the population means are different. If the value of F is small, it means that the differences between populations are not significant ( may differ due to error and not treatment).

The critical region is:

F_{k-1;n-k; 1-\alpha } = F_{2;15; 0.99} = 6.36

If F ≥ 3.36, the decision is to reject the null hypothesis.

Looking at the given data:

F= \frac{MSTr}{MSEr}= 11.32653

With this value the decision is to reject the null hypothesis.

Using the p-value method:

p-value: 0.001005

α: 0.01

The p-value is less than the significance level, the decision is to reject the null hypothesis.

At a level of 5%, there is significant evidence to say that at least one of the population means of the production ratio of the assembly lines A, B and C is different than the others.

b) In this item, you have to stop paying attention to the production ratio of the assembly line A to compare the population means of the production ratio of lines B and C.

(I'll use the same subscripts to be congruent with part a.)

The parameter to estimate is μ₂ - μ₃

The populations are the same as before, so you can still assume that the study variables have a normal distribution and their population variances are unknown but equal. The statistic to use under these conditions, since the sample sizes are 6 for both assembly lines, is a pooled-t for two independent variables with unknown but equal population variances.

t=  (X[bar]₂ - X[bar]₃) - ( μ₂ - μ₃) ~t_{n_2+n_3-2}

Sa√(1/n₂+1/n₃)

The formula for the interval is:

(X[bar]₂ - X[bar]₃) ± t_{n_2+n_3-2; 1 - \alpha /2}* Sa\sqrt{*\frac{1}{n_2} + \frac{1}{n_3} }

Sa^{2} = \frac{(n_2-1)*S_2^2+ (n_3-1)*S_3^2}{n_2+n_3-2}

Sa^{2} = \frac{(5*0.67)+ (5*0.7)}{6+6-2}

Sa^{2} = 0.685

Sa= 0.827 ≅ 0.83

t_{n_2+n_3-2;1-\alpha /2}= t_{10;0.995} = 3.169

X[bar]₂ = 43.33

X[bar]₃ = 41.5

(43.33-41.5) ± 3.169 * *0.83\sqrt{*\frac{1}{6} + \frac{1}{6} }

1.83 ± 3.169 * 0.479

[0.31; 3.35]

With a confidence level of 99% you'd expect that the difference of the population means of the production rate of the assemly lines B and C.

I hope it helps!

8 0
1 year ago
The prices of three t-shirts styles are $24, $30 and $36. the probability of choosing a $24 t-shirt is 1/6. the probability of c
Slav-nsk [51]

\text{Answer} : \text{The expected value of a t-shirt is \$31.}

Explanation:

Since we have given that

The prices of three t-shirts styles  i.e $24, $30, $36 with their probability is given by

\frac{1}{6}, \frac{1}{2},\frac{1}{3}

As we know that,

E(X)= \sum_{1}^{3}x_iP(x_i)

\text{where} x_i \text{ is the prices of t- shirts styles}

Now,

x_1= \$24 , x_2=\$30 , x_3=$36

and

P(x_1)=\frac{1}{6},P(x_2)=\frac{1}{2}, P(x_3)=\frac{1}{3}

So,

E(X)= 24\times \frac{1}{6}+30\times\frac{1}{2}+36\times \frac{1}{3}\\=4+15+12\\=31

So, the expected value of a t-shirt = $31.

4 0
2 years ago
If one worker can assemble 9 products per hour, and another worker can assemble 6 products per hour, how long will it take them
leva [86]

Answer:

  3 hours 20 minutes

Step-by-step explanation:

Together, the workers can assemble 9 + 6 = 15 products per hour. So the assembly of 50 products will take ...

  (50 products)/(15 products/hour) = 50/15 hours = 3 1/3 hours

The two workers can assemble 50 products in 3 1/3 hours.

3 0
2 years ago
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