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Snowcat [4.5K]
2 years ago
5

What is the average speed of a runner if he ran 2 1/3 of a mile in 20 minutes?

Mathematics
2 answers:
lesya [120]2 years ago
7 0
7 MPH because 2 1/3
in 20 minutes. So you multiply 20 by 3 you get 60. Then you multiply 2 by 3 you get 6. Then you multiply 1/3 x 3 and you get 1. 6=1=7                    Hope This Helps
dmitriy555 [2]2 years ago
4 0

Answer:

The average speed of the runner is 7 miles per hour.

Step-by-step explanation:

<u>Given</u>:

Distance ran by 2\frac{ 1}{3} miles

Time taken  by the runner = 20 minutes.

<u>To find</u>:

The average speed of a runner=?

<u>Solution</u>:

Now, we know that ,

distance = speed x time

Then, 2\frac{ 1}{3} miles = average speed x 20 minutes  

=> average speed = \frac{(2 \frac{1}{3} miles)}{(20 minutes)}

=> average speed = (\frac{(2 x 3 + 1)}{3} miles)}{(20\times\frac{1}{60} hours)

=> average speed=\frac{(\frac{(6+1)}{3})}{(\frac{20}{60})}

=> average speed = \frac{ (\frac{7}{3})}{(\frac{1}{3})}

=>average speed = \frac{7}{3}\times\frac{3}{1}

=>average speed = 7

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LMN is a straight angle. Find m LMP and m NMP​
viva [34]

Answer:

(-16x + 13)° + (-20x + 23)° = 180° ( St. angle)

-16x° + 13° - 20x° + 23° = 180°

-4x° + 36° = 180°

-4x° = 180°-36°

-4x° = 144°

-x° = 144°/4

-x° = -36°

x° = 36°

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3 0
2 years ago
1, 32, 243, 1,024, 3,125____ what is the next number in the pattern
rosijanka [135]
Heyya

I think the pattern is (n+1)^5

1=1^5
32 = 2^5
243 = 3^5
1024 = 4^5
3125 =5^5

Then the next number should be 6^5 = 7776
Hope you get it
8 0
2 years ago
Read 2 more answers
Ava wants to figure out the average speed she is driving. She starts checking her car’s clock at mile marker 0. It takes her 4 m
VLD [36.1K]
<h2>Answer:</h2>

The average speed of car is:

                 0.75 miles per minutes.

The equation of line is:

                    n=\dfrac{3}{4}t

<h2>Step-by-step solution:</h2>

The table that describes the time and number of  miles marked is given by:

Time       Miles

  0              0

  4               3

  8               6

Clearly we could observe that with the increase in time by every 4   minutes the number of mile increases by 3.

i.e. the average speed is calculated as the ratio of change in miles to the change in time.

Hence,

Average\ Speed=\dfrac{3-0}{4-0}\\\\\\i.e.\\\\\\Average\ Speed=\dfrac{3}{4}=0.75

Hence, the average speed=0.75 miles per minutes.

Also we will find the equation of the lines that related the miles and time by using the two-point formula.

i.e. any line passing through (a,b) and (c,d) is calculated by using the formula:

y-b=\dfrac{d-b}{c-a}\times (x-a)

Here (a,b)=(0,0) and (c,d)=(4,3)

i.e. the equation is given by:

n-0=\dfrac{3-0}{4-0}\times (t-0)\\\\i.e.\\\\n=\dfrac{3}{4}t

6 0
2 years ago
Read 2 more answers
Brian buys a computer for £4300. It depreciates at a rate of 3% per year. How much will it be worth in 6 years? Give your answer
aalyn [17]

Answer:

3526

Step-by-step explanation:

4300×3%=129

129×6=774

4300_774= 3526

4 0
2 years ago
Read 2 more answers
When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let
vladimir1956 [14]

Answer:

a) P(X ≤ 2) = 0.87

b)  P(X ≥ 5) = 0.01

c) P(1 ≤ X ≤ 4) = 0.71

d) P ( X = 0 ) = 0.28

e) σ(X) = 1.09 , E(X) = 1.25

Step-by-step explanation:

Given:

- Let X = the number of defective boards in a random sample of size n = 25, so X ~ Bin(25, 0.05)

Where, n = 25 and p = 0.05

Find:

(a) Determine P(X ≤ 2).(b) Determine P(X ≥ 5).(c) Determine P(1 ≤ X ≤ 4).(d) What is the probability that none of the 25 boards is defective?(e) Calculate the expected value and standard deviation of X.

Solution:

- The probability mass function for a binomial distribution is given by:

                         P ( X = x ) = nCr * (p)^r * ( 1 - p )^(n-r)

a) P(X ≤ 2):

                         P(X ≤ 2) = P ( X = 0 ) + P ( X = 1 ) + P ( X = 2 )

                         = (0.95)^25 + 25*0.05*0.95^24 + 25C2*0.05^2*0.95^23

                         = 0.87

b) P(X ≥ 5):

            P(X ≥ 5) = 1 - [P ( X = 0 ) + P ( X = 1 ) + P ( X = 2 ) + P ( X = 3 ) + P(X=4)

            = 1 - [ 0.87 + 25C3*0.05^3*0.95^22 + 25C4*0.05^4*0.95^21]

            = 1 - 0.98994

            = 0.01

c) P(1 ≤ X ≤ 4):

            P(1 ≤ X ≤ 4) = P ( X = 1 ) + P ( X = 2 ) + P ( X = 3 ) + P(X=4)

            = ( 0.87 - 0.95^25) + 0.11994

           = 0.71

d) P( X = 0 )

            P ( X = 0 ) = 0.95^25 = 0.28

e) E(X) & σ(X):

            E(X) = n*p

            E(X) = 25*0.05 = 1.25

            σ(X) = sqrt ( Var (X) )

            σ(X) = sqrt ( n*p*(1-p) ) = sqrt ( 25*0.05*0.95 )

            σ(X) = 1.09

4 0
2 years ago
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