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sesenic [268]
1 year ago
13

Thrifty Supply Store normally sells candy bars for $0.59. Today they are running a special 2 candy bars for $0.99. How much woul

d you save if you bought 10 candy bars at the sale price rather than at the regular price?
Mathematics
2 answers:
yaroslaw [1]1 year ago
7 0
At regular price the 10 candy bars would cost $5.90 (0.59×10=5.90). At the sale price the 10 candy bars cost $4.95 (0.99×5 = 4.95). So you would save $0.95 (as 5.90-4.95 =0.95).
ASHA 777 [7]1 year ago
6 0
Cost of candy bars at regular price = 
0.59 x 10  = $ 5.9

Cost after discount =
0.99 x 5  =  $ 4.95

The amount that you save = 
$ 5.9 - $ 4.95   = $ 0.95

Hope this helps
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The condo costs $163,000, earns $2,986 per month, spends no more than 25% of her income, then if she pays $33,000 for the down payment, the remaining amount would be $130,000. Since 20% of the initial cost is only $32,600, she can adjust her down payment to 20.25% of the initial cost so that the annual payments would be less.
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What is 27 players for 12 spots expressed as a rate?
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Answer:

9 p 4 s

Step-by-step explanation:

That's the answer.

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1 year ago
Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of s
Elenna [48]

I will rewrite the question for better understanding:

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighborhood. It takes Ashley 2/3 of a minute to prepare one bag. It takes each of her friends 75% longer to prepare a bag. How many hours will it take Ashley and 4 of her friends to prepare 1575 bags of samples?

Answer:

  • <em><u>5.3 hours</u></em>

Explanation:

<u>1) Time it takes Ashley to preprate one bag: </u>

  • 2/3 min

<u>2) Time it takes each friend of Ashley: 75% more than 2/3 min</u>

  • 75% × 2/3 min = 0.75 × 2/3 min = 3/4 × 2/3 min= 2/4 min = 1/2 min = 0.5 min
  • 2/3 min + 1/2 min = 7/6 min

<u>3) Time it takes Ashley and the 4 friends working along to prepare one bag:</u>

  • Convert each time into a rate, since you can set that the total rate of Ashley along with her four friends is equal to the sum of each rate:

  • Rate of Ashley: 1 bag / (2/3) min = 3/2 bag/min

  • Rate of each friend: 1 bag / (7/6) min = 6/7 bag/min

  • Rate of Ashley and 4 friends = 3/2 bag/min + 4 × 6/7 bag/min = (3/2 +24/7) bag/min = 69/14 bag/min

<u>4) Time of prepare 1575 bags of samples:</u>

  • time = number of bags / number of bags per min = 1,575 bags / (69/14) bags/min = 319.56 min

<u>5) Convert minutes to hours:</u>

  • 356.56 min × 1 hour / 60 min = 5.3 hours
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1 year ago
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Answer:

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Step-by-step explanation:

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A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0
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