Answer:
Pr(X>1540.2) = 0.0655
Step-by-step explanation:
Expected value of large bottle,
E(Large) = 1016
Expected value of small bottle,
E(small) = 510
Expected value of total
E(total) = 1016 + 510 = 1526
So the new mean is 1526
Find standard deviation of new amount by variance
Variance of large bottle,
v(large) = 8^2 = 64
Variance of small bottle,
v(small) = 5^2 = 25
Variance of total
v(total) = 64+25 = 89
So the new standard deviation
sd(new) = sqrt(89) = 9.434
Find probability using the new mean and s.d.
Pr(X>1540.2)
Z score, z = (x-mean)/sd
= (1540.2 - 1526)/9.434
= 1.505
value in z score
P(z<1.51) = 0.9345
For probability of x > 1540.2
P(z > 1.51) = 1 - 0.9345 = 0.0655
Answer:
The p-value should be higher than 0.05
Step-by-step explanation:
solution is found below
Answer:
$12159 per year.
Step-by-step explanation:
If I invest $x each year at the simple interest of 7.5%, then the first $x will grow for 35 years, the second $x will grow for 34 years and so on.
So, the total amount that will grow after 35 years by investing $x at the start of each year at the rate of 7.5% simple interest will be given by

= ![35x + \frac{x \times 7.5}{100} [35 + 34 + 33 + ......... + 1]](https://tex.z-dn.net/?f=35x%20%2B%20%5Cfrac%7Bx%20%5Ctimes%207.5%7D%7B100%7D%20%5B35%20%2B%2034%20%2B%2033%20%2B%20.........%20%2B%201%5D)
= ![35x + \frac{x \times 7.5}{100} [\frac{1}{2} (35) (35 + 1)]](https://tex.z-dn.net/?f=35x%20%2B%20%5Cfrac%7Bx%20%5Ctimes%207.5%7D%7B100%7D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%2835%29%20%2835%20%2B%201%29%5D)
{Since sum of n natural numbers is given by
}
= 35x + 47.25x
= 82.25x
Now, given that the final amount will be i million dollars = $1000000
So, 82.25x = 1000000
⇒ x = $12,158. 05 ≈ $12159
Therefore. I have to invest $12159 per year. (Answer)
Answer:

Step-by-step explanation:
The computation of the area of kite ABCD is shown below:
Given data
AC = 10 ;
BD = 6
As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal
Now the area of quadrilateral when the diagonals are given
So, it is

where,

So, the area of the quadrilateral is
