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Ede4ka [16]
2 years ago
11

Matthew ran 3/8 mile and then walked 7/10 mile. Which pair of fractions can he use to find how far he went in all? (A 15/40 and

28/40 (B 35/40 and 21/40 (C 35/40 and 37/40 (D 30/80 and 70/80 *Please Help*
Mathematics
2 answers:
Strike441 [17]2 years ago
7 0
Before we could add these numbers, 3/8 and 7/10 need a common denominator. Both 8 and 10 go into 40.

8 goes into 40 five times
3/8= (3*5)/40 = 15/40

10 goes into 40 four times
7/10= (7*4)/40= 28/40

ANSWER: A) 15/40 and 28/40

Hope this helps! :)
emmasim [6.3K]2 years ago
5 0

Answer:

Before we could add these numbers, 3/8 and 7/10 need a common denominator. Both 8 and 10 go into 40.

8 goes into 40 five times

3/8= (3*5)/40 = 15/40

10 goes into 40 four times

7/10= (7*4)/40= 28/40

ANSWER: A) 15/40 and 28/40

Hope this helps! :)

Step-by-step explanation:

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Step-by-step explanation:

Jim's work evaluating 2(\frac{3}{5}) ^{3} is shown:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})=2(\frac{3X3X3}{5})=2(\frac{27}{5})=\frac{54}{5}

If you look at the Second step, the exponent is taken over only the numerator. It should have been taken over both the numerator and denominator as shown below.

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})

The correct workings therefore is:

2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})=2(\frac{3X3X3}{5X5X5})=2(\frac{27}{125})=\frac{54}{125}

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