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madam [21]
2 years ago
13

Brad buys two packages of mushrooms. He paid $11.25 for 2/3 lb of Cremini mushrooms and $7.99 for 1/2 lb of Chanterelle mushroom

s. Which mushroom cost less per pound?
Cremini mushrooms cost less by $0.10
Chanterelle mushrooms cost less by $0.10
Chanterelle mushrooms cost less by $0.90
Cremini mushrooms cost less by $0.90
Mathematics
2 answers:
Anna35 [415]2 years ago
6 0

Answer:

Step-by-step explanation:

Cost of 1 lb of Cremini mushrooms= 11.25×3/2=33.75/2=16.875 $≈$16.88

Cost of 1 lb of Chanterelle mushrooms=7.99×2/1=$15.98

Chanterelle mushrooms cost 16.88-15.98=$0.90 less

vlabodo [156]2 years ago
5 0

Answer:

C. (Chanterelle mushrooms cost less by $0.90)

Step-by-step explanation:

Divide 11.25 by 2/3, for the total amount of pound for the Cremini.

Do the same thing for Chanterelle, but the numbers given for it.

We than find out that Cremini=16.87, and Chanterelle=15.98

Now that we know Cremini is more that Chanterelle, we need to find the difference, by subtracting The bigger number by the smaller number.

Our answer is 0.89, but we will round it to 0.90.

Now we know that the Cremini costs more by $0.90, and the Chanterelle costs less by $0.90

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Given: The coordinates of triangle PQR are P(0, 0), Q(2a, 0), and R(2b, 2c).
masha68 [24]

Answer:

The line containing the midpoints of two sides of a triangle is parallel to the third side ⇒ proved down

Step-by-step explanation:

* Lets revise the rules of the midpoint and the slope to prove the

  problem

- The slope of a line whose endpoints are (x1 , y1) and (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid-point of a line whose endpoints are (x1 , y1) and (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

* Lets solve the problem

- PQR is a triangle of vertices P (0 , 0) , Q (2a , 0) , R (2b , 2c)

- Lets find the mid-poits of PQ called A

∵ Point P is (x1 , y1) and point Q is (x2 , y2)

∴ x1 = 0 , x2 = 2a and y1 = 0 , y2 = 0

∵ A is the mid-point of PQ

∴ A=(\frac{0+2a}{2},\frac{0+0}{2})=(\frac{2a}{2},\frac{0}{2})=(a,0)

- Lets find the mid-poits of PR which called B

∵ Point P is (x1 , y1) and point R is (x2 , y2)

∴ x1 = 0 , x2 = 2b and y1 = 0 , y2 = 2c

∵ B is the mid-point of PR

∴ B=(\frac{0+2b}{2},\frac{0+2c}{2})=(\frac{2b}{2},\frac{2c}{2})=(b,c)

- The parallel line have equal slopes, so lets find the slopes of AB and

  QR to prove that they have same slopes then they are parallel

# Slope of AB

∵ Point A is (x1 , y1) and point B is (x2 , y2)

∵ Point A = (a , 0) and point B = (b , c)

∴ x1 = a , x2 = b and y1 = 0 and y2 = c

∴ The slope of AB is m=\frac{c-0}{b-a}=\frac{c}{b-a}

# Slope of QR

∵ Point Q is (x1 , y1) and point R is (x2 , y2)

∵ Point Q = (2a , 0) and point R = (2b , 2c)

∴ x1 = 2a , x2 = 2b and y1 = 0 and y2 = 2c

∴ The slope of AB is m=\frac{2c-0}{2b-2a}=\frac{2c}{2(b-c)}=\frac{c}{b-a}

∵ The slopes of AB and QR are equal

∴ AB // QR

∵ AB is the line containing the midpoints of PQ and PR of Δ PQR

∵ QR is the third side of the triangle

∴ The line containing the midpoints of two sides of a triangle is parallel

  to the third side

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