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Anuta_ua [19.1K]

2 years ago

7

Suzy’s Sculpting gym charges a $10 Application fee and $12 per month for membership. Tami’s Toning does not charge an applicatio

n fee, but charges $14 per month for membership. After how many months will the total cost of membership be for both gyms?

1 answer:

borishaifa [10]2 years ago

8 0

Answer:

hi have a nice day luv ya

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If the parent function is y = 3x, which is the function of the graph? y = 0.5(3)x y = 2(3)x y = −2(3)x y = −0.5(3)x

german

Answer: If I remember correctly, the answer should be <em>y=-2(3)^x. </em>

7 0

2 years ago

A group of students formed a circle during a game.The circumference of the circle was about 43.96 feet,and the diameter of the c

Alchen [17]

Answer:

A group of students formed a circle during a game.The circumference of the circle was about 43.96 feet,and the diameter of the circle was 14 feet.Which expression best represents the value of π?

The expression which represents the value of π is option C from the attachment that is π = 43.96/14

Step-by-step explanation:

Given:

Circumference of the circle = 43.96 feet

Diameter f the circle = 14 feet

So,

We know that :

Circumference of the circle = $2(\pi )r$ or $(\pi)d$

Re-arranging the formula:

⇒ $(\pi)d = Circumference\ (C)$

⇒ $(\pi )d =C$

⇒ $\frac{\pi\times d}{d}=\frac{C}{d}$

⇒ $\pi =\frac{C}{d}$

Plugging the numeric values:

⇒ $\pi =\frac{43.96}{14}$

So the expression for π is 43.96/ 14,and option C is the correct choice.

4 0

2 years ago

25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct

soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of $2\pi$ and a vertical compression.

Step-by-step explanation:

We are given the parent function as $y= \cot x$

It is given that, transformations are applied to the parent function in order to obtain the function $y=0.5\cot (0.5x)$ i.e. $y=\frac{1}{2}\cot (\frac{x}{2})$

That is, we see that,

The parent function $y= \cot x$ is stretched horizontally by the factor of $\frac{1}{2}$ which gives the function $y=\cot (\frac{x}{2})$ .

Further, the function is compressed vertically by the factor of $\frac{1}{2}$ which gives the function $y=\frac{1}{2}\cot (\frac{x}{2})$ .

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

Since, the period of $y= \cot x$ is $\pi$ , so the period of $y=\frac{1}{2}\cot (\frac{x}{2})$ is $\frac{\pi}{1/2}$ = $2\pi$

Hence, we get option C is correct.

3 0

2 years ago

PLEASE HELP!! laboratory tests show that the lives of light bulbs are normally distributed with a mean of 750 hours and a standa

Lunna [17]

Answer:

P = 0.0215 = 2.15%

Step-by-step explanation:

First we need to convert the values of 900 and 975 to standard scores using the equation:

$z = \frac{x - \mu}{\sigma}$

Where z is the standard value, x is the original value, $\mu$ is the mean and $\sigma$ is the standard deviation. So we have that:

standard value of 900: $z = \frac{900 - 750}{75} = 2$

standard value of 975: $z = \frac{975 - 750}{75} = 3$

Now, we just need to look at the standard distribution table (z-table) for the values of z = 2 and z = 3:

z = 2 -> p_2 = 0.9772

z = 3 -> p_3 = 0.9987

We want the interval between 900 and 975 hours, so we need the interval between z = 2 and z = 3, so we just need to subtract their p-values:

P = p_3 - p_2 = 0.9987 - 0.9772 = 0.0215

So the probability is 0.0215 = 2.15%

8 0

2 years ago

An element with mass 430 grams decays by 27.4% per minute. How much of the element is remaining after 19 minutes, to the nearest

nadya68 [22]

The equation for exponential decay is $y=a*b^x$ , where <em>a</em> is the initial amount, <em>b</em> = 1 + <em>r</em> (the growth rate as a decimal number) and <em>x</em> is the number of time periods (in this case, minutes). Substituting the information we have:
$y=430(1+-0.274)^1^9
\\=430(1-0.274)^1^9
\\=430(0.726)^1^9=0.98$ . To the nearest tenth of a gram, this would be 1.0 grams.

7 0

2 years ago