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ser-zykov [4K]
2 years ago
8

the numbers below follow a pattern 0.006 0.06 0.6 6 what are the next two numbers in the pattern and what is the relationship be

tween the terms in the pattern
Mathematics
2 answers:
dolphi86 [110]2 years ago
5 0

<u>Answers</u>

60

600

Relationship between term: The next term is ten times the previous term.

<u>Explanations</u>

0.006 = 6/1000

0.06 = 6/100

0.6 = 6/10

6 = 6/1 This is a geometric sequence, where the common ratio is 10.

0.6/0.06 = 6/0.6 = 0.06/0.006 = 10

To get next number we simply multiply the previous number by 10.

The terms relate to each other in that the next term is 10 times the previous term.

aleksklad [387]2 years ago
3 0
66, then 666, I am assuming cause of how it goes .006 ---> .06 --> .6 ---> 6
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EXPLANATION

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Answer:

a

The Null hypothesis represented as

     H_0: \mu_1 -  \mu_2  = 0

   

The Alternative hypothesis represented as

     H_a: \mu_1 -  \mu_2  <  0

b

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Step-by-step explanation:

From the question we are told that

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    The  sample size for graduates is  n_1 =  300

     The sample  mean for graduates is \= x _1 =  148

      The sample  standard deviation for graduates is \sigma_1  =  16

    The  sample size for under-graduates is n _2 = 350

         The sample  mean for under-graduates is \= x _2 =  153

         The sample  standard deviation for graduates is \sigma_2  =  21

The Null hypothesis represented as

     H_0: \mu_1 -  \mu_2  = 0

   

The Alternative hypothesis represented as

     H_a: \mu_1 -  \mu_2  <  0

Where \mu_1 \ and \  \mu_2 are the population mean

  Now the test statistic is mathematically represented as

          t =  \frac{(\= x_1 - \= x_2 ) }{ \sqrt{ \frac{ (n_1 - 1 )\sigma_1 ^2 + (n_2 - 1)\sigma_2^2}{n_1 +n_2 -2} }  * \sqrt{ \frac{1}{n_1}  + \frac{1}{n_2} } }

substituting values

       t =  \frac{(148 - 153 ) }{ \sqrt{ \frac{ (300- 1 )16 ^2 + (350 - 1) 21^2}{300 +350 -2} }  * \sqrt{ \frac{1}{300}  + \frac{1}{350} } }

      t = -3.37

The p-values is mathematically evaluated as

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The above answer is gotten using a p-value calculator  at (0.05) level of significance

     Looking the p-value we see that it is less than the level of significance (0.05)  so Null hypothesis is rejected

Hence there is insufficient evidence to conclude that graduate students score higher, on average, on the HPI than undergraduate students

   

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