<span>F for Frank, A or Alice.
F(initial)=1.95 inches
A(initial)=1.50 inches
Frank's equation at .25 inches per year and t representing year variable.
F=1.95+.25t
Alice's equation at .40 inches per year and t representing year variable.
A=1.5+.40t
To figure out how old they will be when their beaks are the same lengths set the equations equal to eachother as the equations are length.
1.95+.25t=1.5+.40t
.45=.15t
t=3 years</span>
First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
More
First, you divide 2042/5950 which is about 0.4036, then you move the decimal 2 spaces to the right which is about 40.4, which means that 40% of Tom's income is his mortgage, higher than the average
Answer is
<span>g(x) = 2.5x + 25
</span>5 newspapers, 2.5(5) + 25 = 12.5 + 25 = 37.5
20 newspapers, 2.5(20) + 25 = 50 + 25 = 75