In a swimming competition, Peter swam 600m and Gabriel swam 2km .What is the ratio of Peter’s distance to Gabriel’s? Give your a
1 answer:
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Answer:
a.[144;158]$
b. The parameter estimated is the population mean of the weekly expenses on the food of American families.
Step-by-step explanation:
Hello!
The study variable for this problem is "Weekly expenses on food spent by an American family"($)
For a sample n=1014 American families the corresponding sample mean is x[bar]=$151
It is stated that for the 95%CI the margin of error is ±$7
a.
The confidence interval that estimates the population mean is constructed as the "estimator ± margin of error" for example, under a Standard Normal distribution the formula for the confidence interval is:
[x[bar]±*(δ/√n)]
For the sample taken it is:
[151±7]
The inferior limit is 144$
The superior limit is 158$
b.
The parameter estimated is the population mean of the weekly expenses on the food of American families.
The confidence level of an interval is the probability under which it is built. This probability indicates that if they build 100 confidence intervals, we expect 95 to contain the value of the population mean we are trying to estimate.
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Answer:
a. We fail reject to the null hypothesis because zo = -5.84 < 1.65 = zα and P-value = 1 (approximately)
b. The confidence Interval for u1 - u2 is; 6.79 ≤ u1 - u2
c. The power of the test = 1 -
β = 0.998736
d. The sample size is adequate because the power of the test is approximately 1
Step-by-step explanation:
Given
Standard Deviations; σ1 = σ2 = 1.0 psi
Size: n1 = 10; n2 = 12
X = 162.5; Y = 155.0
Let X1, X2....Xn be a random sample from Population 1
Let Y1, Y2....Yn be a random sample from Population 2
We assume that both population are normal and the two are independent.
Therefore, the test statistic
Z = (X - Y - (u1 - u2))/√(σ1²/n1 + σ2²/n2)
See attachment for explanation
