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2 years ago

16z+29z=pz−v solve for z

Mathematics

2 answers:

gtnhenbr [62]2 years ago

8 0

Answer:

$z = \frac{-v}{45-p}$

Step-by-step explanation:

Given the equation:

$16z+29z =pz-v$ ....[1]

Solve for z:

Subtract pz from both sides in [1] we have;

$16z+29z-pz = -v$

taking z common we have;

$z(16+29-p)= -v$

Combine like terms;

$z(45-p)= -v$

Divide both sides by (45-p) we have;

$z = \frac{-v}{45-p}$

Therefore, the value of z is, $z = \frac{-v}{45-p}$

Dmitry [639]2 years ago

6 0

16z + 29z = pz - v....for z
45z = pz - v
45z - pz = -v
z(45 - p) = -v
z = -v / (45 - p) <==

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The extraneous solutions are the solutions that does not work in the original equation.

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