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scZoUnD [109]
2 years ago
11

The cross section of rectangular prism A measures 3 units by 2 units. The cross section of triangular prism B has a base that me

asures 4 units and a height of 3 units. If the length of each prism is 3.61 units, which statement is true? rectangular prism A , with a cross-section that is parallel to its respective basetriangular prism B, with a cross-section that is parallel to its respective base Volume A = one half(Volume B) Volume A = 2(Volume B) Volume A = one third(Volume B) Volume A = Volume B
Mathematics
1 answer:
mamaluj [8]2 years ago
6 0

Answer:

Volume A= one third

Step-by-step explanation:

Use volume B

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The tip jar at a sandwich shop has been found to have a dollar value 0.65ℎ +1.25, where ℎ is the number of hours since the shop
DedPeter [7]

Answer:

The intial value is 1.25

Step-by-step explanation:

7 0
2 years ago
11/12​−6/1​q+6/5​q−3/1​, Combine like terms to create an equivalent expression.
Nikolay [14]

Answer: -\frac{25}{12} -\frac{24q}{5}

Step-by-step explanation:

\frac{11}{12} -\frac{6}{1} q+\frac{6}{5}q-\frac{3}{1}

\frac{11}{12} -6q+ \frac{6q}{5} -\frac{3}{1}

\frac{11}{12}-6q \frac{6q}{5} -3

(\frac{11}{12} -3)+(-6q+\frac{6q}{5} )

-\frac{25}{12}- \frac{24q}{5}

Simplify three times, collect like terms and simplify again, how to collect like terms see their differences and then put them into groups, for example I put all the numbers without variables on one side and all the numbers with variables on another.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)  

- Cutiepatutie ☺❀❤

4 0
2 years ago
Read 2 more answers
Which expression is equivalent to the equation?
IrinaK [193]

Answer:

Option 1

Step-by-step explanation:

The given equation equals 3072, so find the other equation that equals 3072.

Option 1 = 3072 - correct

Option 2 = 432 - wrong

Option 3 = 2883 - wrong

Option 4 = 432 - wrong

I hope this helps!

4 0
1 year ago
A jet flies 425 km from Ottawa to Québec at rate v + 60. On the return flight, the
Marina CMI [18]

Answer:

a. \frac{- 42,500}{(v + 60)(v - 40)}

Step-by-step Explanation:

Given:

Distance Ottawa to Québec = 425 km

Initial flight rate = v + 60

Return flight rate = v - 40

t = \frac{d}{r}

Required:

Flight times difference of the initial and return flights

Solution:

=>Flight time of the initial flight:

t = \frac{d}{r}

t = \frac{425}{v + 60}

=>Flight time of the return flight:

t = \frac{425}{v - 40}

=>Difference in flight times:

\frac{425}{v + 60} - \frac{425}{v - 40}

\frac{425(v - 40) -425(v + 60)}{(v + 60)(v - 40)}

\frac{425(v) - 425(40) -425(v) -425(+60)}{(v + 60)(v - 40)}

\frac{425v - 17000 -425v - 25500}{(v + 60)(v - 40)}

\frac{425v - 425v - 17000 - 25500}{(v + 60)(v - 40)}

\frac{- 42,500}{(v + 60)(v - 40)}

3 0
2 years ago
To graph the function g(x) = (x – 5)2 – 9, shift the graph of f(x) = x2 5 units and 9 units.
Monica [59]
To graph the function g(x) = (x<span> – 5)</span>2<span> – 9, shift the graph of </span>f(x<span>) = </span>x2 <span>✔ right 
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4 0
1 year ago
Read 2 more answers
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