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alekssr [168]
2 years ago
12

At Norris Middle School 11 out of 22 students bike to school. At Lewis and Clark Middle School 14 out of 28

Mathematics
1 answer:
Darina [25.2K]2 years ago
5 0
Both ratios are equivalent due to the fact that 11/22 as a simplified fraction makes 1/2 and 14/28 also makes 1/2 if simplified.
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Milla and Luka are 3 kilometers apart and walking toward each other. Milla's average speed is 5 kilometers per hour and Luka's i
pantera1 [17]
It's B 5t+4t=3 thats the original answer
3 0
2 years ago
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Average speed of Car 1 = 45 mph. Average speed of Car 2 = 65 mph. Time elapsed between start of Car 1 and start of Car 2 = 18 mi
Art [367]
Is this math? if so let me know maybe I could try to help
3 0
2 years ago
Solve the trigonometric equation in the interval [0, 2π). Give the exact value, if possible; otherwise, round your answer to two
svp [43]

Answer:

θ∈{\frac{\pi }{8},\frac{5\pi }{8},\frac{9\pi }{8},\frac{13\pi }{8}}

Explanation:

The given equation is

sin(2\theta )-cos(2\theta )=0

\Rightarrow sin(2\theta )=cos(2\theta )\\\\\therefore \frac{sin(2\theta )}{cos(2\theta )}=1\\\\tan(2\theta )=1\\\\\therefore 2\theta =n\pi +\frac{\pi}{4}\\\\\therefore \theta =\frac{n\pi }{2}+\frac{\pi }{8}

Applying values on 'n' we obtain values of θ that beling to [0,2π)

For n=0, θ=\frac{\pi }{8}

For n=1, θ =\frac{5\pi }{8}

For n=2,θ =\frac{9\pi }{8}

For n=3,θ =\frac{13\pi }{8}

6 0
2 years ago
Sin(11∘)cos(19∘)+cos(11∘)sin(19∘)
sergij07 [2.7K]
Recall that:

sin(A + B) = sinAcosB + cosAsinB

Therefore:

sin11°cos19° + cos11°sin19° = sin(11° + 19°)

                                                   = sin30° = 0.5            

I hope this explains it.
3 0
2 years ago
in germany, VAT is at 19% Jeremy buys a calculator in germny for €58.31 This price includes VAT Find the amount of VAT paid by
Len [333]

We can use this equation to solve this problem:

<span>t=p+<span>(p⋅r)</span></span>

Where:

t is the total price paid: 58.31 for this problem

p is the price before taxes: What we are solving for in this problem.

r is the tax or VAT rate: 19% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 19% can be written as <span>19100</span> or 0.19.

Substituting and solving for p gives:

<span>58.31=p+<span>(p⋅0.19)</span></span>

<span>58.31=1p+0.19p</span>

<span>58.31=<span>(1+0.19)</span>p</span>

<span>58.31=1.19p</span>

<span><span>58.311.19</span>=<span><span>1.19p</span>1.19</span></span>

<span>49=<span><span>1.19p</span>1.19</span></span>

<span>49=p</span>

<span>p=49</span>

Now, we can find how much the VAT was by taking 19% of 49:

<span>19%×49=0.19×49=9.31</span>

Another was to solve this is to subtract the price without the tax or VAT from the total price giving:

<span>58.31−49=<span>9.31</span></span>

4 0
2 years ago
Read 2 more answers
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