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2 years ago

Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

7 0

Answer:

The width of lot B is 11 feet, so option A is correct.

Step-by-step explanation:

Given:

Two rectangular properties share a common side.

Lot A is 33 feet wide and 42 feet long.

The combined area of the lots = 1,848 square feet.

To find:

How many feet wide is Lot B?

Solution:

we know that, area of a rectangle is length x breadth

Then area of lot A = 33 x 42 = 1386 square feet.

And area of lot B = width x 42

Now, we are given that, total area = 1848

area of lot A + area of lot B = 1848

1386 + width x 42 = 1848

width x 42 = 1848 – 1386

width x 42 = 462

$width =\frac{42}{462}$

width = 11

Hence, the width of lot B is 11 feet, so option A is correct.

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FinnZ [79.3K]

<h3>Answer: Choice A</h3>

The first line shown in choice A is $a_1 = -2$ which means "the first term is -2"

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first term = -2

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2 years ago

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Answer:

Part A: The test average for the math class after completing 2 tests is 81

Part B: The test average for the science class after completing 2 tests is 83

Part C: The science class had the higher average test score after completing the test 4.

Step-by-step explanation:

The average test score for math class is given by the linear function, f(x) = 0.5·x + 80

The data for the average test score for science g(x) are;

x, q(x)

1, 81

2, 83

3, 85

Part A: The average test score for math after completing test 2 is given as follows;

f(2) = 0.5×2 + 80 = 81

∴ The test average for the math class after completing 2 tests = 81

Part B:

The average test score for science after completing test 2 is given from the table as at x = 2, g(2) = 83

∴ The test average for the science class after completing 2 tests = 83

Part C: After completing 4 tests, we have for the math class, f(4) = 0.5×4 + 80 = 82

For the science class, it is observed that common difference between each subsequent test score average is 2, therefore, the average test score, for the fourth test is 2 added to the average test score after the third test, which gives;

Average test score, after completing the fourth test for the science class, g(4) = 85 + 2 = 87

Since g(4) > f(4) the science class had the higher average test score after completing the test 4.

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2 years ago

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