Question

Two rectangular properties share a common side. Lot A is 33 feet wide and 42 feet long.

Answer 1

Answer:

The width of lot B is 11 feet, so option A is correct.

Step-by-step explanation:

Given:

• Two rectangular properties share a common side.  

• Lot A is 33 feet wide and 42 feet long.  

• The combined area of the lots = 1,848 square feet.  

To find:

How many feet wide is Lot B?  

Solution:

we know that, area of a rectangle is length x breadth

Then area of lot A = 33 x 42 = 1386 square feet.

And area of lot B = width x 42

Now, we are given that, total area = 1848  

area of lot A + area of lot B = 1848  

1386 + width x 42 = 1848  

width x 42 = 1848 – 1386  

width x 42 = 462  

$width =\frac{42}{462}$

width = 11

Hence, the width of lot B is 11 feet, so option A is correct.