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Solnce55 [7]
2 years ago
13

The alpha level that a researcher sets at the beginning of the experiment is the level to which he wishes to limit the probabili

ty of making the error of______________ . Identify the boundaries that separate the extreme samples from the samples that are more obviously consistent with the null hypothesis. Assume the null hypothesis is nondirectional, meaning that the critical region is split across both tails of the distribution. The z-score boundaries at an alpha level α = .05 are:___________
Mathematics
1 answer:
Lelu [443]2 years ago
8 0

Answer:

Kindly check explanation

Step-by-step explanation:

The alpha level set at the beginning of of an experiment is used by the researcher to the limit the probability if making a type 1 error. The type 1 error is committed when a true null hypothesis is incorrectly rejected.

The type 2 error on the other hand is committed when fail to reject a false null hypothesis.

Hence, in other to forestall the risk of incorrectly rejecting a true null hypothesis, the alpha level is set.

When critical region is split across both tails of the distribution, The z-score boundaries at an alpha level α = .05

α = .05 (95% confidence level)

When region is split into 2:

α/2 = .05/2

α/2 = 0.025

Loooking up the z table for the Zscore with probability of 0.025

Zscore = ±1.96

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How many terms in the arithmetic sequence(2,4,6,8....) will give sum of 600
andriy [413]

Answer:

  24 terms

Step-by-step explanation:

The sum of an arithmetic sequence is the average of the first and last terms, multiplied by the number of terms. The last term is given by ...

  an = a1 + (n-1)d

We have a sequence with first term a1 = 2 and common difference d = 2. So the last term is ...

  an = 2+ 2(n -1) = 2n

Then the average of first and last terms times the number of terms is ...

  Sn = 600 = n(2 + 2n)/2 = n(n+1) . . . . . . close to n²

We can solve the quadratic in n, or we can estimate the value of n as the integer just below the square root of 600.

  √600 ≈ 24.5

so we believe n = 24.

_____

<em>Check</em>

  S24 = 24·25 = 600 . . . . . . as required.

8 0
2 years ago
In the diagram of circle A, what is the measure of ∠XYZ?<br><br> 35°<br> 70°<br> 75°<br> 140°
Mademuasel [1]

Answer:   First Option is correct.

Step-by-step explanation:

Since we have given that

Measure of arc WZ = 175°

Measure of ∠XAZ = 105°

We need to find the measure of ∠XYZ.

As we know the angle subtended at the center is the average of the measure of arc intercepted by it angle and its vertical angles.

\frac{175^\circ+\angle XYZ}{2}=105^\circ\\\\175^\circ+\angle XYZ=210^\circ\\\\\angle XYZ=210^\circ-175^\circ\\\\\angle XYZ=35^\circ

Hence, the value of  ∠XYZ is 35°.

Hence, First Option is correct.

3 0
2 years ago
Read 2 more answers
What algebraic expression could represent the average of 2x, x + 3, and 6x?
Gre4nikov [31]

Answer:

(5x = 2 = 3 +8a

Step-by-step explanation:

8 0
2 years ago
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The product of a binomial and a trinomial is x 3 + 3 x 2 − x + 2 x 2 + 6 x − 2. Which expression is equivalent to this product a
valkas [14]

Answer:

x^3+3x^2+5x+2

Step-by-step explanation:

The product of a binomial and a trinomial is

x^3+3x^2-x+2 \times 2 +6x-2

we have to simplify that

x^3+3x^2-x+4+6x-2

bringing the like terms together we get

x^3+3x^2-x+6x+4-2

-x+6x = 5x

-2+4 = 2

hence our expression becomes

x^3+3x^2-x+6x+4-2=x^3+3x^2+5x+2

5 0
2 years ago
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Consider the inverse function. Which conclusions can be drawn about f(x) = x2 + 2? Select three options. f(x) has a limited rang
PolarNik [594]

Answer:

f(x) has a limited range

f(x) has a maximum at the point (0, 2)

f(x) has a y-intercept at the point (0, 2).

Step-by-step explanation:

Given the function;

f(x) = x^2+2

The domain is the value of the input variables for which the function will exist. According to the expression given, the function exists on all real values of x. The same goes with range which deals with the output values. It also exists on all real values from 2 and above.

Hence f(x) have a limited range (since values less than 2 are not included compare to domain that exists on all real values) and does not have a restricted domain.

For the x intercept, x intercept occur at y = 0

substitute y = 0 into the function and get y

if y = f(x)

y = x^2+2

0 = x^2 + 2

x^2 = -2

x = 2i

Hence  f(x) does not have an x-intercept of (2, 0)

For the y intercept, y intercept occur at x = 0

substitute x = 0 into the function and get y

if y = f(x)

y = x^2+2

y = 0^2 + 2

y = 2

Hence  f(x) has a y-intercept at point (0, 2)

f(x) is at maximum if d(fx))/dx = 0

d(fx))/dx  = 2x

since  d(fx))/dx  = 0

0 = 2x

x = 0

substitute x = 0 into the function

f(x) = x^2 + 2

y = 0^2+2

y = 2

Hence f(x) has a maximum at the point (0, 2)

5 0
1 year ago
Read 2 more answers
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