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2 years ago

A clothing design company pays two different people to design its T-shirts.

Mathematics

2 answers:

Art [367]2 years ago

8 0

Answer: 0, 7.5

Step-by-step explanation:

irina [24]2 years ago

5 0

Answer: D

Step-by-step explanation:

You might be interested in

The two-way frequency table below shows data on student behavior and the use of positive phone calls home as an incentive for go

dusya [7]

Answer:

From the frequency table, let's calculate the row total.

Row total for phone call = 19 + 9 = 28

Row total for no phone call = 8 +6 = 14

To calculate their respective row relative frequencies, let's use:

Row relative freq = $\frac{freq.}{Row total}$

Now, the two-way frequency table will be computed as:

For phone call:

Desirable behavior = $\frac{19}{28} = 0.67857$ ≈0.69

Undesirable behaviour = $\frac{9}{28} = 0.3214$ ≈0.32

No phone call:

Desirable behaviour = $\frac{8}{14} = 0.5714$ ≈ 0.57

Undesirable behaviour = $\frac{6}{14} = 0.4286$ ≈ 0.43

The complete two-way table is attached.

8 0

2 years ago

Liam is swimming at 3 kilometers per hour. How long will it take Liam to travel 4.5 kilometers?

kkurt [141]

Answer:

One hour and thirty minutes.

Explanation:

3km = 1 hour

1.5km = 30 min (half of distance, half of time)

4.5km = 1 hour and 30 min

5 0

1 year ago

Read 2 more answers

A product is composed of four parts. In order for the product to function properly in a given situation, each of the parts must

svet-max [94.6K]

Answer:

P(working product) = .99*.99*.96*.96 = .0.903

Step-by-step explanation:

For the product to work, all four probabilities must come to pass, so that

P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)

where

P(Part-1) = 0.96

P(Part-2) = 0.96

P(Part-3) = 0.99

P(Part-4) = 0.99

As all parts are independent, so the formula is P(A∩B) = P(A)*P(B)

P (Working Product) = P(Part-1)*P(Part-2)*P(Part-3)*P(Part-4)

P (Working Product) = 0.96*0.96*0.96*0.99*0.99

P(Working Product) = 0.903

3 0

1 year ago

A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr

erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

$p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034$

The estimated standard error is:

$\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316$

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

$LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096$

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

8 0

1 year ago

A box of chocolates contains five milk chocolates, three dark chocolates, and four white chocolates. You randomly select and eat

PolarNik [594]

Answer:

60/220

Step-by-step explanation:

we use combination,

$(\frac{5}{1} ) \times ( \frac{4}{1} ) \times ( \frac{3}{1} )$