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FinnZ [79.3K]
2 years ago
6

One of the largest pizzas ever made had a diameter of 80 yards. To the nearest square yard, what is the area of this pizza?

Mathematics
1 answer:
ladessa [460]2 years ago
5 0

Answer: The area is 5024 yrd^2

Step-by-step explanation:

80 is the diameter to we need to divide it by 2 to find the radius

80/2= 40

A= 3.14* 40^2

A = 3.14 * 1600

A= 5024

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Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av
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The answer is 6(0.65-t)

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Jim Ryan, an owner of a Burger King restaurant, assumes that his restaurant will need a new roof in 7 years. He estimates the ro
Lelu [443]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$9000\\
P=\textit{original amount deposited}\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &7
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6 0
2 years ago
T varies inversely as the square root of u.<br>t = 3 when u = 4.<br>Find t when u = 49.​
RoseWind [281]

Answer:

t = \frac{6}{7}

Step-by-step explanation:

Given that t varies inversely as the square root of u then the equation relating them is

t = \frac{k}{\sqrt{u} } ← k is the constant of variation

To find k use the condition t = 3 when u = 4, thus

k = t\sqrt{u} = 3 × \sqrt{4} = 3 × 2 = 6

t = \frac{6}{\sqrt{u} } ← equation of variation

When u = 49, then

t = \frac{6}{\sqrt{49} } = \frac{6}{7}

6 0
1 year ago
The following data represent the length of life in
Natali [406]

Answer:

(a) For the stem-and-leaf plot, we need to organise all data in columns, one column is the stem and a second column is the leaf, but in this case, stems are going to be the digits to the left of the decimal point, and leafs are the digits to the right of the decimal point:

<u>Stem</u>            <u> Leaf </u>

0             2 2 2 3 3 4 5 7

1              0 2 3 5 5 8

2             0 3 5

3             0 3

4             0 5 7

5             0 5 6 9

6             0 0 0 5

(b) Relative frequency distribution.

Remember that, a relative frequency is calculated dividing the absolute frequency by the total data, in this case, we approximated to the hundredth.

Length of life    Absolute Frequency      Relative Frequency     % Relative Freq.

0.2                              3                                        0.1                                10

0.3                              2                                        0.07                              7

0.4                              1                                         0.03                              3

0.5                              1                                         0.03                              3

0.7                              1                                         0.03                              3

1.0                               1                                         0.03                              3

1.2                               1                                         0.03                              3

1.3                               1                                         0.03                              3

1.5                               2                                        0.07                              7

1.8                               1                                         0.03                              3

2.0                              1                                         0.03                              3

2.3                              1                                         0.03                              3

2.5                              1                                         0.03                              3

3.0                              1                                         0.03                              3

3.3                              1                                         0.03                              3

4.0                              1                                         0.03                              3

4.5                              1                                         0.03                              3

4.7                              1                                         0.03                              3

5.0                              1                                         0.03                              3

5.5                              1                                         0.03                              3

5.6                              1                                         0.03                              3

5.9                              1                                         0.03                              3

6.0                              3                                        0.10                               10

6.5                              1                                         0.03                              3

Total                          30                                          

(c)

To calculate the sample mean we need to sum all number, which results: 83.9. Then, we divide this result to the total 30, which result: 2.80.

The sample range is the difference between the highest and the lowest value: 6.5 - 0.2 = 6.3.

The sample standard deviation is calculated trough the following process:

Step 1: Subtract the mean from each number.

Step 2: Square each result.

Step 3: Add the squared deviations.

Step 4: Divide the sum by one less the total.

Step 5: Take the square root, and there you have it.

Doing this steps, the result is 2.22.

This last process is attached:

4 0
1 year ago
30,45,x,100; The median is 51
Alex Ar [27]
To solve for x, you must first understand how the median was calculated out of the given set of numbers. Without looking at the given median value, we can see that we cannot get the median by process of elimination since there are an even amount of numbers in this particular set. Therefore, we must average the two closest values to what should be the median.

In this case, the values are "45" and "x". If we pretend that we know the value of the variable "x" (for example we will pretend that x is 55), then we should have an equation that looks like this: (45+55) ÷ 2 = [median]. What this equation is doing is adding the two closest values to the median (45 and 55) and dividing it by 2, the number of values we are averaging. Now we can solve this equation and simplify it to 100 ÷ 2 which is 50, our median.

So if they give us the median instead of the x value, then we can rewrite the equation to fit your request: (45+x) ÷ 2 = 51. Now we can solve for x:

1. Multiply by 2
(45+x) = 102

2. Subtract 45
x = 57

The x value for your question is 57.
3 0
2 years ago
Read 2 more answers
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