First let's write out the inequality before choosing a graph.
x apples each weighing 1/3 of a pound: 1/3x
y pounds of grapes: y
So...
1/3x + y < 5
The maximum weight is 4 pounds since the total weight of both the grapes and apples are less than 5.
In the y-axis, the first, third, and fourth graphs already exceed the capacity of 5 pounds.
So, by process of elimination, the correct graph for this problem is the second one.
Answer:
30
Step-by-step explanation:
14+16 1. Break it down 14 is equal to 10+4 16 is equal to 10+6 2. Add the biggest numbers together first 10+10 = 20 3. Add the smaller numbers together 6+4 = 10 4. Add all of the numbers together 20+10 = 30
Answer:
Option B.
Step-by-step explanation:
It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.
RT is altitude on side SQ, ST=9, TQ=16 and SR=x.
In ΔSRQ and ΔSTR,
(Reflexive property)
(Right angle)
By AA property of similarity,

Corresponding parts of similar triangles are proportional.

Substitute the given values.


On cross multiplication we get


Taking square root on both sides.


The value of x is 15. Therefore, the correct option is B.
Answer: Kai
Step-by-step explanation:
I did the assignment and got it correct
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:

P(B) is the probability that the selected student plays basketball.
Then:

P(A and B) is the probability that the selected student plays soccer and basketball:

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.