Answer:
θ∈{}
Explanation:
The given equation is
Applying values on 'n' we obtain values of θ that beling to [0,2π)
For n=0, θ=
For n=1, θ =
For n=2,θ =
For n=3,θ =
For each exercise draw circle O with radius 12. Then draw radii OA and OB to form an angle with the measure named. Find the leng
1 answer:
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<h2>Answer:</h2>
In the 5th year
<h2>Step-by-step explanation:</h2>For the first year, the salary is 1.2million = 1,200,000
For the second year, the salary is 1.2million + 75000 = 1,200,000 + 75,000 = 1,275,000
.
.
.
For the last year, the salary is 1.5million = 1,500,000
This gives the following sequence...
1,200,000 1,275,000 . . . 1,500,000
This follows an arithmetic progression with an increment of 75,000.
<em>Remember that,</em>
The last term, L, of an arithmetic progression is given by;
L = a + (n - 1)d ---------------(i)
<em>Where;</em>
a = first term of the sequence
n = number of terms in the sequence (which is the number of years)
d = the common difference or increment of the sequence
<em>From the given sequence,</em>
a = 1,200,000 [which is the first salary]
d = 75,000 [which is the increment in salary]
L = 1,500,000 [which is the maximum salary]
<em>Substitute these values into equation (i) as follows;</em>
1,500,000 = 1,200,00 + (n - 1) 75,000
1,500,000 - 1,200,000 = 75,000(n-1)
300,000 = 75,000(n - 1)
4 = n - 1
n = 5
Therefore, in the 5th year the maximum salary will be reached.
Answer:
(–1.4, 1.5)
Step-by-step explanation:
The blue line and the purple line are the lines corresponding to the equations of interest. Their point of intersection is in the 2nd quadrant, so is nearest to ...
(–1.4, 1.5)
__
It can be useful to understand that for equations in standard form:
ax +by = c
the x- and y-intercepts are ...
- x-intercept: c/a . . . . value of x for y = 0
- y-intercept: c/b . . . . value of y for x = 0
__
For the equations of interest, the first has intercepts of ...
x=2/3, y=1/2 . . . . graphed line makes a 1st-quadrant triangle with the axes (blue line)
And the second has intercepts of ...
x=-1, y=-4 . . . . graphed line makes a 3rd-quadrant triangle with the axes (purple line)
Since the purple line has a steeper slope, the point of intersection of the lines will be in the 2nd quadrant. There is only one 2nd-quadrant answer choice: (-1.4, 1.5).
