Question

Find the product. (a2)(2a3)(a2 – 8a + 9) 2a7 – 16a6 + 18a5 2a7 – 16a6 – 18a5 2a8 – 16a7 + 18a6 2a12 – 16a7 + 18a6 consider the degree of each polynomial in the problem. the first factor has a degree of . the second factor has a degree of . the third factor has a degree of . the product has a degree of .

Answer 1

Answer: $2x^7 -16a^6 +18a^5$

Step-by-step explanation: Given expression $(a^2)(2a^3)(a^2-8a + 9)$.

The first factor $(a^2)$ has a degree of : 2 because power of a is 2.

The second factor $(2a^3)$ has a degree of : 3 because power of a is 3.

The third factor $(a^2-8a + 9)$ has a degree of : 2 because highest power of a is 2.

Let us multiply them now:

$(a^2)(2a^3)(a^2-8a + 9).$

First we would multiply $(a^2)(2a^3)$.

According to product rule of exponents, we would add the powers of a.

Therefore,

$(a^2)(2a^3) = 2a^{2+3}= 2a^5$

Now, we need to distribute $2a^5$ over $(a^2-8a + 9)$

Therefore,

$(2a^5)(a^2-8a + 9)= 2a^{5+2} -16a^{5+1}+18a^5$

=$2x^7 -16a^6 +18a^5$

Highest power of resulting polynomial $2x^7 -16a^6 +18a^5$ is 7.

Therefore, The product has a degree of 7.

Answer 2

Answer:

Step-by-step explanation:

A  

2a7 – 16a6 + 18a5