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k0ka [10]
1 year ago
15

A company that manufactures small canoes has a fixed cost of $ 18 comma 000$18,000. It costs $ 120$120 to produce each canoe. Th

e selling price is $ 240$240 per canoe.​ (In solving this​ exercise, let x represent the number of canoes produced and​ sold.)a. Write the cost function.
​C(x)equals=
nothing ​ (Type an expression using x as the​ variable.)
b. Write the revenue function.
​R(x)equals=
nothing  ​(Type an expression using x as the​ variable.)
c. Determine the​ break-even point.
Mathematics
1 answer:
Scilla [17]1 year ago
4 0
If the company makes 1 canoe only, then the cost is, the fixed cost plus how much it costs for the 1 canoe, or
180,000 + 1*120

if it makes 2 canoes
180,000 + 2*120
3 canoes   180,000 + 3*120
4canoes   180,000 + 4*120
x canoes  180,000 + x*120

so... we dunno what "x" is, but whatever "x" maybe, the cost ends up as 180,000 + x*120, or 180,000 + 120x

now, let's see the revenue
1 canoe 1 * 240
2 canoes 2*240
3 canoes 3*240
x canoes x*240

so.. whatever "x" maybe, the Revenue is x*240 or 240x

break-even point is when, the amount of expenses and earnings cancel each other out, or, there's no profit, but there's no loss either, same amount that's spent is also earned back

so, the break-even point occurs when Revenue = Cost

180,000 + 120x = 240x     <--- solve for "x"
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Meeting at least one person with the flu in thirteen random encounters on campus when the infection rate is 2% (2 in 100 people
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Answer:

23.1% probability of meeting at least one person with the flu

Step-by-step explanation:

For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Infection rate of 2%

This means that p = 0.02

Thirteen random encounters

This means that n = 13

Probability of meeting at least one person with the flu

Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.02)^{0}.(0.98)^{13} = 0.7690

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23.1% probability of meeting at least one person with the flu

6 0
1 year ago
Use Lagrange multipliers to find three positive numbers whose sum is 210 and whose product is maximum. (Enter your answers as a
nalin [4]

Answer: the three positive numbers are; 70, 70, 70

Step-by-step explanation:

Given that sum is equal = 210

Lets ( x, y, z ) be the three positive numbers

such that

x + y + z = 210

what is the maximum of xyz

take f(x,y,z) = xyz

Q(x,y,z) = 0

x + y + z -210 = 0

consider the function

F(x,y,z) = f(x,y,z) + λQ(x,y,z)

F = xyz + λ(x+y+z-210)

dF/dx = 0 ⇒ yz + λ(1) = 0 ⇒ λ = -yz   ..............equ(1)

dF/dy = 0 ⇒ xz + λ(1) = 0 ⇒ λ = -xz.................equ(2)

dF/dz = 0 ⇒ xy + λ(1) = 0 ⇒ λ = -xy...............equ(3)

Now

equ(1)/equ(2) ⇒ λ/λ = -yz/-xz ⇒ x = +y

equ(1)/equ(3) ⇒ λ/λ = - yz/-xy ⇒ x = +z

⇒ y = z = x

by substitution

x + y + z = 210

x + x + x = 210

3x = 210

x = 210/3 = 70

∴ x, y, z = 70, 70 ,70

MAXIMUM

∛xyz = 70  { when x = y = z = 70}

7 0
1 year ago
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