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vaieri [72.5K]
2 years ago
7

Martin and three of his friends take turns driving on a trip. The gas mileage for their car ranges from 28.94 to 24.56 miles per

gallon. Each friend drives between 58 and 64 miles, so Martin estimates they will need about 7 gallons of fuel for their trip. Is this a reasonable estimate?
A. No, the estimate should be higher.
B. No, the estimate should be lower.
Mathematics
1 answer:
mart [117]2 years ago
8 0

Answer:

A. No, the estimate should be higher

Step-by-step explanation:

To determine the maximum number of gallons of fuel the car can consume, we express this as;

Maximum miles driven=highest consumption per gallon×Maximum gallons

where;

Maximum miles driven per person=64 mile

Maximum miles driven=64×4=256 miles

highest consumption per gallon=24.56 miles per gallon

Maximum gallons=g

replacing;

256=24.56×g

24.56 g=256

g≥256/24.56=10.42 gallons

g≥10.42 gallons

No, the estimate should be higher

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2 years ago
A salesperson receives step commission on sales calculated as follows:
kykrilka [37]

Answer:

$2278.846

Step-by-step explanation:

Given the following commision steps :

8% on first $1000;

12% next $2000;

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Recorded sales for a week :

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Tuesday $3000.00

Wednesday $ 970.00

Thursday $4563.81

Friday $2760.42

This assu es that commision is calculated after weekly sales:

Total:

(1500 + 3000 + 970 + 4563.81 + 2760.42)

= $12794.23

8% on first $1000

0.08 × $1000 = $80

12% of $2000 = $240

20% of $(12794.23 - 3000)

= 0.2 × 9794.23

= 1958.846

Total commision for the week :

$(80 + 240 + 1958.846)

= $2278.846

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2 years ago
Evaluate variable expressions involving integers
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The number of calls coming per minute into a hotel reservation center is Poisson random variable with mean 3.
natima [27]

Answer:

a) 0.05

b) 0.9826

c) 0.000039308

Step-by-step explanation:

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b) For two minutes, the mean is doubled, hence it is 6. In order to calculate the probability of al least two calls arriving, we calculate first the probability of the complementary event: At most 1 call will arrive. For that probability, we need to sum the probabilities of 0 and 1.

P_X(0) = e^{-6}

P_X(1) = \frac{e^{-6}*6^1}{1!} = 6*e^{-6}

Hence,

P(X \geq 2) = 1-P(X < 2) = 1- 7*e^{-6} = 0.9826

c) For five minutes the mean is 15. We need to sum the probabilities of 0, 1 and 2.

P_X(0) = e^{-15}

P_X(1) = e^{15}*15

P_X(2) = \frac{e^{-15}*15^2}{2!} = 112.5*e^{-15}

As a result,

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Practically 0

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2 years ago
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