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Eddi Din [679]
2 years ago
15

Solve the system by substitution

Mathematics
1 answer:
kumpel [21]2 years ago
6 0
<h3>Answer:</h3>

  (x, y) = (1, 4)

<h3>Step-by-step explanation:</h3>

<u>Given:</u>

  • -4.5x-2y=-12.5
  • 3.25x-y=-0.75

<u>Find:</u>

  x and y using the method of substitution

<u>Solution:</u>

To solve a system of equations by <em>substitution</em>, you find an expression for one of the variables in terms of the others, then substitute that wherever that variable is used*. Usually, you choose <em>one of the equations</em> to solve for the variable you're going to substitute for, then you make the substitution into the <em>remaining</em> equation(s).

Since the coefficient of y in the second equation is -1, it is convenient to solve for y in that equation, then use the resulting expression to substitute for y in the first equation.

  3.25x = y - 0.75 . . . . . . add y

  3.25x + 0.75 = y . . . . . . add 0.75

Using this expression in place of y in the first equation, we have ...

  -4.5x -2(3.25x +0.75) = -12.5

  -11x -1.5 = -12.5 . . . . . . . simplify

  -11x = -11 . . . . . . . . . . . . . add 1.5

  x = 1 . . . . . . . . . . . . . . . . . divide by -11

We can substitute this value into the equation we have for y:

  y = 3.25x +0.75 = 3.25·1 + 0.75

  y = 4

The solution to the system of equations is (x, y) = (1, 4).

_____

* There's no point in substituting for the variable in the equation you used to find the expression. It will give you no useful information. Here, that would look like ...

  3.5x -(3.5x+0.75) = 0.75 . . . . . . . . substitute for y in the second equation

  0.75 = 0.75 . . . . . . . always true. Not a useful substitution.

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At first, I thought this was going to be a dog of a bear of a problem,
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Each of these pyramids has the same base area and the
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jasenka [17]
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