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suter [353]
2 years ago
14

The axis of symmetry for the function f(x) = −x2 − 10x + 16 is x = −5. What are the coordinates of the vertex of the graph? (−5,

41) (−5, 56) (−5, 76) (−5, 91)
Mathematics
2 answers:
Umnica [9.8K]2 years ago
8 0
The x-coordinate of the axis os symmetry of a quadratic is the x-coorfinate of its vertex. To find the y-coordinate of the vertex here we would substitute -5 for x in:

f(x) =   - {x}^{2}  - 10x + 16 \\ so \: we \: have \:  \\ f( - 5) =  - ( { - 5)}^{2} - 10( - 5) + 16 \\  =  - 25 + 50 + 16 = 41
The coordinates of the vertex are (-5,41)
Helen [10]2 years ago
8 0

Answer:

The answer is A

Step-by-step explanation:

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