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Mekhanik [1.2K]

2 years ago

12

To order tickets online to a hockey game, there is a processing fee plus the cost per ticket. The cost for 5 tickets is $174.45.

The codt for 8 tickets is $271.95. Write and solve a linear equation to find the total cost to order 13 tickets.

1 answer:

xeze [42]2 years ago

3 0

Wouldn’t the total for 13 tickets be $446.40 ? We already know the cost for 5 and 8 just add it up .... js

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a company makes a profit of $50 per software program and $35 per video game. The company can produce at most 200 software progra

Lynna [10]

Answer:

In order to maximize the profit, should be produced 200 software program and 235 video games per week

Step-by-step explanation:

Let

x ------> the number of software program

y -----> the number of video games

we know that

$x \leq 200$ -----> inequality A

$y \leq 300$ -----> inequality B

$x+y \leq 435$ -----> inequality C

Using a graphing tool

The solution is the shaded area between the positive values fo x and y

see the attached figure

The vertices of the shaded area are

(0,0),(0,300),(135,300),(200,235),(200,0)

The profit function is equal to

$P=50x+35y$

Substitute the value of x and the value of y of each vertices in the profit function

For (0,300) ----- $P=50(0)+35(300)=\$10,500$

For (135,300) ----- $P=50(135)+35(300)=\$17,250$

For (200,235) ----- $P=50(200)+35(235)=\$18,225$

For (200,0) ----- $P=50(200)+35(0)=\$10,000$

therefore

In order to maximize the profit, should be produced 200 software program and 235 video games per week

4 0

2 years ago

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The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballga

cricket20 [7]

<u>Events</u> A and B are called <u>independent</u>, when

$Pr(A\cap B)=Pr(A)\cdot Pr(B),$

otherwise events A and B are <u>dependent</u>.

The events A, B and A∩B are:

A - Jane will go to a ballgame on Monday;
B - Kate will go to a ballgame on Monday;
A∩B - Kate and Jane both go to the ballgame on Monday.

$Pr(A)=0.73,\ Pr(B)=0.61,\ Pr(A\cap B)=0.52.\\ \\ Pr(A)\cdot Pr(B)=0.73\cdot 0.61=0.4453\neq 0.52=Pr(A\cap B).$

Answer: events A and B are dependent

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2 years ago

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ipn [44]

we know that

A <u>geometric sequence</u> is a sequence of numbers in which the ratio between consecutive terms is constant

so

Let

$a1=24 \ a2=24.48\ a3=24.97\ a4=25.47$

$\frac{a2}{a1} = \frac{24.48}{24}= 1.02$

$a2=a1*1.02$

$\frac{a3}{a2} = \frac{24.97}{24.48}= 1.02$

$a3=a2*1.02$

$\frac{a4}{a3} = \frac{25.47}{24.97}= 1.02$

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therefore

The common ratio is equal to $1.02$

<u>the answer is</u>

The common ratio is 1.02

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Factorise 15x+ 18y???

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Oh dear~This can only be simplified。
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Consider that 1 inch = 2.54 centimeters. Which three statements are true for converting 18 feet to centimeters?

serg [7]

Answer:

There are 548.64 cm in 18 feet.

Step-by-step explanation:

We know that, 1 inch = 2.54 centimeters.

We need to convert 18 feet to centimeters

Also, 1 foot = 12 inch

Firstly we will convert 18 feet to inch.

18 feet = 12 × 18 inch

= 216 inch

Now to convert 18 feet to centimeters, multiply 216 inch by 2.54 cm as follows :

216 inch = 2.54×216 centimeters

= 548.64 cm

Hence, there are 548.64 cm in 18 feet.

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2 years ago