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Leviafan [203]
1 year ago
6

Dylan is comparing prices of yarn for a project. The prices and quantities from four stores are shown.

Mathematics
2 answers:
Delicious77 [7]1 year ago
8 0

Answer:

Store 3

Step-by-step explanation:

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Ksenya-84 [330]1 year ago
3 0
Store 3
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A coat was originally priced at $50. It went on sale for $35. What was the percent that the cost was discounted?
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Answer: 30 % Off

Step-by-step explanation:

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2 years ago
The graph of the parent function f(x) = x3 is translated to form the graph of g(x) = (x − 4)3 − 7. The point (0, 0) on the graph
tensa zangetsu [6.8K]

Answer:

The point (0, 0) in the graph of f(x) corresponds to the point (4, -7) in the graph of g(x)

Step-by-step explanation:

Notice that when we start with the function f(x)=x^3, and then transform it into the function: g(x)=(x-4)^3-7

what we have done is to translate the graph of the function horizontally 4 units to the right (via subtracting 4 from the variable x), and 7 units vertically down (via subtracting 7 to the full functional expression).

Therefore, the point (0, 0) in the first function, will now appeared translated 4 units to the right (from x = 0 to x = 4) and 7 units down (from y = 0 to y = -7).

then the point (0, 0) after the translation becomes: (4, -7)

7 0
2 years ago
Read 2 more answers
Factor 125x9 + 64. (5x3 – 4)(25x6 + 20x3 + 16) (5x3 – 4)(25x3 + 20x3 + 16) (5x3 + 4)(25x6 – 20x3 + 16) (5x3 + 4)(25x3 – 20x3 + 1
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(5x^3 + 4)(25x^6 - 20x3 +16)  remember factoring the cubes?
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How many significant figures does 0.0560
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Let P be a point not on the line L that passes through the points Q and R. The distance d from the point P to the line L is d =
Goshia [24]

Answer:

Distance from point (0,1,1) to the given line is zero.

Step-by-step explanation:

Given parametric equations of line,

x=2t, y=5-2t, z=1+t

To find distance from (0,1,1), we have to eliminate t from above equations so that,

y=5-2t=5-x\implies x+y=5=4+1=4+z-t=4+z-\frac{1}{2}x

\implies 3x+2y-2z-8=0\hfill (1)

whose direction ratioes are (l,m,n)=(3,2,-2) and distance fro point (a,b,c)=(0,1,1) is given by,

\frac{al+bm+cn}{\sqrt{l62+m^2+n^2}}=\frac{(3\times 0)+(2\times 1)+(-2)(1)}{\sqrt{3^2+2^2+(-2)^2}}=\frac{0+2-2}{\sqrt{17}}=0

Distance between point (0,1,1) and (1) is zero. That is point 90,1,1) is lies on the line (1).

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2 years ago
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