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1 year ago

Dylan is comparing prices of yarn for a project. The prices and quantities from four stores are shown.

Mathematics

2 answers:

Delicious77 [7]1 year ago

8 0

Answer:

Store 3

Step-by-step explanation:

PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST PLEASE MARK ME BRAINLIEST

Ksenya-84 [330]1 year ago

3 0

Store 3
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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

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2 years ago

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

kifflom [539]

This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.

2x + 3y = 1470

2x + 3(0) = 1470

2x = 1470

x = 735

Your furthest point on the x axis is (735,0).

Do the same for y.

2x + 3y = 1470.

2(0) + 3y = 1470

3y= 1470

y= 490

Your highest point is (0,490).

Now that both are plotted, draw a straight line connecting the two points. There's your graph.

Check

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2 years ago

To increase an amount by 7% what single multiplier would you use?

vazorg [7]

You would multiply by 1.7

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2 years ago

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H is directly proportional to the square root of p h= 5.4 when p = 1.44 find h when p =2.89

LenKa [72]

Answer:

h=7.65

Step-by-step explanation:

H is directly proportional to the square root of p;

Let k be the constant of proportionality;

Means h=k√p

This means for corresponding points of h and p such that (h1,p1) and (h2,p2) we have;

h1/√p1=h2/√p2

Let h= 5.4 when p = 1.44 and h when p =2.89 be respectively (h1,p1) and (h2,p2)

So that

5.4/√1.44=h/√2.89

5.4/√1.44 ×√2.89 = h

7.65= h

h=7.65

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2 years ago

Leah likes the number 400 but not 500. She likes 900 but not 999.

Bezzdna [24]

The answer is 1,200

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2 years ago

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