One centimenter is 0.01 meters. So, you can write the measures as

Once this rewriting is done, getting the total length
is quite trivial, since all measurements are in the same unit, and we can simply sum everything:

Answer: 
Step-by-step explanation:
We know that:

Where "d" is distance, "r" is rate and "t" is time.
Solved for the time "t":

The first step is to convert the distance from miles to feet.
Since
, we get:

Knowing that:

We can substitute values into
in order to find the time in seconds:

Since:

The time in minutes is:

Answer:
See below in bold.
Step-by-step explanation:
This is the vertex form of a parabola which opens upwards.
To find the x intercept put h(x) = 0:
(x + 1)^2 - 4 = 0
(x + 1)^2 = 4
x + 1 = +/- 2
x = (-3, 0) an (1, 0) are the x-intercepts.
For the y-intercept we put x = 0
y = (0+1)^2 - 4 = -3
y-intercept = (0, -3).
The vertex is (-1, -4).
Axis of symmetry is x = -1.
Answer:
The sports car, because it has less mass and therefore less inertia
Step-by-step explanation:
When an object has less inertia it is easier to be put into and out of motion, and a sports car would obviously weigh less than a van.
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.