(x) = arcsec(x) − 8x
f'(x) = d/dx( arcsec(x) −
8x )
<span> 1/xsqrt( x^2 - 1) - 8</span>
f'(x) = 0
1/xsqrt( x^2 - 1) - 8 = 0
8 x sqrt (x^2-1) = 1
<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>
64 x^2 ( x^2 - 1) = 1
64 x^4 - 64 x^2 =1
64 x^4 - 64 x^2 - 1 = 0
x = 1.00766 , - 1.00766
<span> x = - 1.00766</span>
f(- 1.00766) = arcsec(-
1.00766) − 8( - 1.00766)
f( - 1.00766 ) = 11.07949
x = 1.00766
f(1.00766) =
arcsec(1.00766) − 8( 1.00766)
f(1.00766 ) = -7.93790
relative maximum (x, y) =
(- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 ,
-7.93790 )
First lets write down our starting conditions:
we have 22 gallons and it has 16% of ammonia
16% of 22 gallons is
A = 16/100*22 = 3,52 gallons
Now since only watter is evaporating that means that in second scenario after some watter evaporated there is still 3,52 gallons of ammonia. But now those 3,52 gallons of ammonia represent 24% of total mixture. So now we go other way.
24 % is 3,52 gallons
100% is x gallons
x = 100/24*3,52 = 14.667 gallons
That means that he has to evaporate
22 - 14.6667 = 7,333 gallons of water.
Possible outcomes :
Heads Heads
Heads Tails
Tails Tails
Tails Heads
Probability of matching : 2/4 = 0.5
Torin should agree since the proposal is fair
Answer: The volume of container that holds 460 grams of oil is 500 cm³.
Step-by-step explanation:
Density of olive oil is 
An olive farmer wants to sell bottles that contain 460 grams of oil.
Therefore
Mass of oil = 460 grams
As we know
Hence, the volume of container that holds 460 grams of oil is 500 cm³.
