Ask question

Ask question

All categories

2 years ago

9

Olive oil is a cooking Ingredient. The density of olive oil is 0.92 grams per cubic centimeter. An olive farmer wants to sell bo

ttles that contain
460 grams of oil. What is the volume of the smallest container that holds 460 grams of oll?

1 answer:

sveticcg [70]2 years ago

7 0

Answer: The volume of container that holds 460 grams of oil is 500 cm³.

Step-by-step explanation:

Density of olive oil is $0.92 grams/(centimetre )^3$

An olive farmer wants to sell bottles that contain 460 grams of oil.

Therefore

Mass of oil = 460 grams

As we know

$\text {Density}= \dfrac{\text{Mass}}{\text{Volume}} \\\\\Rightarrow 0.92= \dfrac{460}{\text{Volume}} \\\\\Rightarrow \text{Volume}= \dfrac{460}{0.92} = 500$

Hence, the volume of container that holds 460 grams of oil is 500 cm³.

You might be interested in

You want to test the effects of water aerobics on resting heart rate. You decide to test two different levels of exercise (water

DochEvi [55]

Answer:

The correct option is;

A). Randomized block design

Step-by-step explanation:

In a randomized block design the experimental units or subjects of the experiment are separated into subgroups known as blocks with the property that the the variability (difference) of the parameters within the blocks are lesser than the variability between block, such that the treatment of the research or experiment are assigned differently to each block

The groups can therefore comprise of the following;

Group 1

15 men and 15 women to perform water aerobics for 30 minutes twice a week

Group 2

15 men and 15 women to perform water aerobics for 60 minutes once a week

Therefore, the effect of the experiment will be much less attributed to gender than to the durations of the water aerobic exercise.

5 0

2 years ago

x^2+1/2x+1/16=4/9 Factor the perfect-square trinomial on the left side of the equation. (x + )² = 4/9

Nezavi [6.7K]

The missing number is the square-root of the constant term on the left-hand-side, which equals sqrt(1/16)=1/sqrt(16)=1/4.
Check:
(x+1/4)^2=x^2+2*(1/4)x+(1/4)^2=x^2+x/2+1/16. ok

Answer: x= 1/4

5 0

2 years ago

Read 2 more answers

A small school with 60 total students records how many of their students attend on each of the 180 days in a school year. the ma

horrorfan [7]

Answer:

For the sampling distribution,

a) Mean = μₓ = 55.0 students.

b) Standard Deviation = 1.8 students.

Step-by-step explanation:

The complete Question is attached to this solution.

The Central limit theorem explains that for the sampling distribution, the mean is approximately equal to the population mean and the standard deviation of the sampling distribution is related to the population standard deviation through

σₓ = (σ/√n)

where σ = population standard deviation = 4

n = sample size = 5

Mean = population mean

μₓ = μ = 55 students.

Standard deviation

σₓ = (σ/√n) = (4/√5) = 1.789 students = 1.8 students to 1 d.p

Hope this Helps!!!

5 0

2 years ago

A manageress earned £24,500 last year. This year she earns £25,235.

Korolek [52]

Answer:

Step-by-step explanation:

245000 last year

This year 25235

(y2 - y1) / y1)*100 = your percentage change

(where y1=start value and y2=end value)

(( £25.235 - £24.500) / £24.500) * 100 = 0 %

There ain't no percentage change as there needs to be a bigger difference between the two numbers plus u should use the formula

7 0

1 year ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

1 year ago