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Ne4ueva [31]
2 years ago
9

Olive oil is a cooking Ingredient. The density of olive oil is 0.92 grams per cubic centimeter. An olive farmer wants to sell bo

ttles that contain
460 grams of oil. What is the volume of the smallest container that holds 460 grams of oll?​
Mathematics
1 answer:
sveticcg [70]2 years ago
7 0

Answer: The volume of container that holds 460 grams of oil is 500 cm³.

Step-by-step explanation:

Density of olive oil is 0.92 grams/(centimetre )^3

An olive farmer wants to sell bottles that contain  460 grams of oil.

Therefore

Mass of oil  = 460 grams

As we know

\text {Density}= \dfrac{\text{Mass}}{\text{Volume}} \\\\\Rightarrow 0.92= \dfrac{460}{\text{Volume}} \\\\\Rightarrow \text{Volume}= \dfrac{460}{0.92} = 500

Hence, the volume of container that holds 460 grams of oil is 500 cm³.

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According to my study,  current yield is calculated by using the formula Interest or dividends divided by the current price of the security or simple the current price. So the current price in this given question is 102.114 and the interest is 8.1%, we will simply divide the two; 8.1 / 102.114 = 0.07732310947 or approximately .077. The answer is A.
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Chris is making a tabletop. He has 9 tiles that are each 3 1/8 long by 2 3/4 inches wide.
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Substitute the values in:

area = 3 1/8 x 2 3/4

area = 275/32

Multiply this by 9:

275/32 x 9 = 77.34375 in^2

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2 years ago
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The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca
dem82 [27]

Answer:

\frac{4}{663}

Step-by-step explanation:

Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.

A - the first card is 4

B - second card is ace

We have to find probability for

A\bigcap B

P(A) = no of 4s in the deck/total cards = \frac{4}{52} =\frac{1}{13}

After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it

P(B) = no of Aces in 51 cards/51 = \frac{4}{51}

Hence

P(A\bigcap B) = \frac{1}{13} *\frac{4}{51} \\=\frac{4}{663}

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)

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When Val checks her cable bill, she is shocked by her movie-rental bill for the month. Renting movies costs $2.99 for each movie
astraxan [27]

Answer:

She should buy the monthly plan for the unlimited movies rather than pay $2.99 per movie. This is because, the more she pay that amount for each movie, the higher her expenses would become at the end of each month.

For example, let assume, in a month, she 8 free days (Saturday and Sunday). She paying for each movie each of those days would supersede the amount she could have spent assuming she did the unlimited monthly plan of $7.99.

That notwithstanding other days which will feel like watching movies or the public holidays which she would be free to relax.

Step-by-step explanation:

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2 years ago
An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an
kotegsom [21]

Answer:

The mean number of successful surgeries is 1.57.

The variance of the number of successful surgeries is 0.3111.

Step-by-step explanation:

STEP 1

If the tear on the left knee has a rim width of less than 3mm, the probability that the surgery on the left knee will be successful (ls) is 0.90.

That isP(Is)=0.90

.

The probability that the surgery on the left knee will fail (lf) is 0.10. That isP(V)=0.10

.

If the tear on the right knee has a rim width of 3-6 mm, the probability that the surgery on the right knee will be successful (rs) is 0.67. That isP(rs)=0.67

.

The probability that the surgery on the right knee will fail (rf) is 0.33.

That isP(vf)= 0.33

.

Let the random variable X denote the number of successful surgeries. The range of X is{0,1,2)

.

Now find the probabilities associated with the possible values of X. The number of successful surgeries is equal to 0 if the surgeries on both knees fail. Since the surgeries are independent, we have:

P(X = 0)=P(lf and rf)

= P()P(rf)

=(0.10)(0.33)

= 0.033

The number of successful surgeries is equal to 1 if the surgery on one knee is successful and the surgery on the other knee fails, that is

P(X =1)= P((ls and rf) or (if and rs))

= P(Is)P(rf)+P(V)P(rs)

= (0.90)(0.33)+(0.10)(0.67)

= 0.364

The number of successful surgeries is equal to 2 if the surgeries on both knees are successful, that is

P(X = 2)=P(ls and rs)

= P(Is) P(rs)

=(0.90)(0.67)

= 0.603

So, the probability mass function of X is the following

X        0              1               2

f(x)     0.033      0.364      0.603

The mean number of successful surgeries is,

E(X)=∑xP(x)

=(0×0.033) +(1×0.364)+(2×0.603)

=1.57

the mean number of successful surgeries is 1.57

The expected value is obtained by taking the summation of the product of each possible value of the random variable X with its corresponding probabilities. Thus, the mean number of successful surgeries is 1.57.

STEP 2

The variance of the number of successful surgeries is,

Var(X)=∑x²P(x)-(E(x²)

=(0×0.033) + (1 × 0.364) +(2 × 0.603) - (1.57)²

= 2.776 -(1.57)²

=0.3111

The variance of the number of successful surgeries is 0.3111.

6 0
2 years ago
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