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Vanyuwa [196]
2 years ago
6

Oscar and Kim have $22.00 each to spend at a book fair, where all students receive a 30% discount. They both want to purchase a

copy of the same book, which normally sells for $28.50 plus 10% sales tax. To check if he has enough to purchase the book, Oscar takes 30% of $28.50 and subtracts that amount from the normal price. He takes 10% of the discounted selling price and adds it back to find the purchase amount. Kim takes 70% of the normal purchase price and then computes 110% of the reduced price. Is Oscar correct? Is Kim correct? Do they have enough money to purchase the book? Explain your answer using complete sentences, and show your work.
Mathematics
2 answers:
ziro4ka [17]2 years ago
5 0
They are both correct in their computation

(28.5-28.5(.3))+.1(28.5-28.5(.3))=$21.945

28.5(.7)(1.1)=$21.945

And since they each have $22 to spend, they have enough to purchase the book.
bazaltina [42]2 years ago
5 0
Oscar : 0.30(28.50) = 8.55....28.50 - 8.55 = 19.95...0.10(19.95) = 2....19.95 + 2 = 21.95

Kim : 0.7(28.5) = 19.95....1.10(19.95) = 21.95

They are both correct. They both have enough money to buy the book.
They each just did it a little different way. Kim, instead of taking 30% off, and subtracting it from the original price, she multiplied it by 70%...because taking 30% off is just like paying 70%....and instead of taking 10% of the discount price and adding it back to the discount price, she multiplied it by 110%....it is exactly the same thing
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Given that:

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B.  We have to find the probability that the selected fish is male.

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\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

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\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

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D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

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Answer:

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