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slava [35]
2 years ago
10

The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below.

Means and Mean Absolute Deviations of Individual Times of Members of mc011-1.jpg Relay Swim Teams Team A Team B Mean 127.9 s 127.4 s Mean Absolute Deviation 0.26 s 0.23 s The difference of the means is found and then compared to each of the mean absolute deviations. Which is true? The difference between the mean times is about equal to the mean absolute deviation of the data sets. The difference between the mean times is about 2 times the mean absolute deviation of the data sets. The difference between the mean times is about 5 times the mean absolute deviation of the data sets. The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Mathematics
2 answers:
I am Lyosha [343]2 years ago
8 0

Answer:

B should be be your answer

Step-by-step explanation:


shepuryov [24]2 years ago
7 0
See the attached picture for the solution:

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Tan 235° = 2tan20°+ tan215°​
Mariulka [41]

Given :  tan 235 = 2 tan 20 + tan 215

To Find : prove that

Solution:

tan 235 = 2 tan 20 + tan 215

Tan x = Tan (180 + x)

tan 235 = tan ( 180 + 55) = tan55

tan 215 = tan (180 + 35) = tan 35

=> tan 55 = 2tan 20 + tan 35

55 = 20 + 35

=> 20  = 55 - 35

taking Tan both sides

=> Tan 20 = Tan ( 55 - 35)

=> Tan 20  = (Tan55 - Tan35) /(1 + Tan55 . Tan35)

Tan35 = Cot55 = 1/tan55 => Tan55 . Tan35 =1

=> Tan 20  = (Tan 55 - Tan 35) /(1 + 1)

=> Tan 20  = (Tan 55 - Tan 35) /2

=> 2 Tan 20  = Tan 55 - Tan 35

=> 2 Tan 20 +  Tan 35 = Tan 55

=>  tan 55 = 2tan 20 + tan 35

=>  tan 235 = 2tan 20 + tan 215

QED

Hence Proved

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