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slava [35]
1 year ago
10

The means and mean absolute deviations of the individual times of members of two relay swim teams are shown in the table below.

Means and Mean Absolute Deviations of Individual Times of Members of mc011-1.jpg Relay Swim Teams Team A Team B Mean 127.9 s 127.4 s Mean Absolute Deviation 0.26 s 0.23 s The difference of the means is found and then compared to each of the mean absolute deviations. Which is true? The difference between the mean times is about equal to the mean absolute deviation of the data sets. The difference between the mean times is about 2 times the mean absolute deviation of the data sets. The difference between the mean times is about 5 times the mean absolute deviation of the data sets. The difference between the mean times is about 16 times the mean absolute deviation of the data sets.

Mathematics
2 answers:
I am Lyosha [343]1 year ago
8 0

Answer:

B should be be your answer

Step-by-step explanation:


shepuryov [24]1 year ago
7 0
See the attached picture for the solution:

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Kite A B C D is shown. Lines are drawn from point A to point C and from point B to point D and intersect. In the kite, AC = 10 a
Oduvanchick [21]

Answer:

30 u^{2}

Step-by-step explanation:

The computation of the area of kite ABCD is shown below:

Given data

AC = 10 ;

BD = 6

As we can see from the attached figure that the Kite is a quadrilateral as it involves two adjacent sides i.e to be equal

Now the area of quadrilateral when the diagonals are given

So, it is

\text { area of kite }=\frac{1}{2} \times d_{1} d_{2}

where,

d_{1}=10\ and\ d_{2}=6

So, the area of the quadrilateral is

=\frac{1}{2}(10)(6)\\\\=30 u^{2}

4 0
1 year ago
A probability calculator is required on this problem; answer to six decimal places. Suppose we will spin the wheel pictured 400
KiRa [710]

Answer:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=400, p=0.2)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We need to check the conditions in order to use the normal approximation.

np=400*0.2=80 \geq 10

n(1-p)=400*(1-0.2)=320 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=400*0.2=80

\sigma=\sqrt{np(1-p)}=\sqrt{400*0.2(1-0.2)}=8

So then we can approximate the random variable as X \sim N(\mu = 80, \sigma = 8)

And we want this probability:

P(90< X< 110)

We can use the z score formula given by:

z = \frac{x -\mu}{\sigma}

And replacing we got:

P(90< X< 110)= P(\frac{90-80}{8}

And we can find this probability with this difference:

P(90< X< 110)=P(z

And we can find the real value with the following excel code using the binomial distribution:

"=BINOM.DIST(110,400,0.2,TRUE)-BINOM.DIST(89,400,0.2,TRUE)"

And we got 0.118 a very close value from the value obtained using the normal approximation

8 0
2 years ago
The table represents the equation y = 2 – 4x. A 2-column table with 5 rows. The first column is labeled x with entries negative
kherson [118]

The missing value for x=-1 is y=6

Explanation:

It is given that the equation for the table is y=2-4x

The table has 2 column with 5 rows.

Thus, we have,

x       y

-2      10

-1       ---

0        2

1        -2

2       -6

We need to determine the value of y when x=-1

The value of y can be determined by substituting x=-1 in the equation y=2-4x

Thus, we have,

y=2-4(-1)

Multiplying the term within the bracket, we have,

y=2+4

Adding the terms, we have,

y=6

Thus, the value of y when x=-1 is 6.

Hence, the missing value for x=-1 is y=6

7 0
1 year ago
Read 2 more answers
Round 1627187 to the nearest ten?
Eduardwww [97]

Answer:

1627190

Step-by-step explanation:

(see attached for reference)

Given the number 1627187, we can see that the number in the tens place is the number 8.  

How we round this depends on the number immediately to the right of this number. (i.e the digit in the ones place)

Case 1: If the digit in the ones place is less less than 5, then the number in the tens place remains the same and replace all the digits to its right with zeros

Case 2: If the digit in the ones places is 5 or greater, then we increase the digit in the tens place and replace all the digits to its right with zeros.

In our case, the digit in the ones places is 7, this greater than 5, hence according to Case 2 above, we increase the digit in the tens place by one (from 8 to 9) and replace all the digits to its right by zeros giving us:

1627190

7 0
1 year ago
Read 2 more answers
The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years. Based on th
elena-14-01-66 [18.8K]

Answer: 0.9013

Step-by-step explanation:

Given mean, u = 10, standard deviation =8

P(X) =P(Z= X - u /S)

We are to find P(X> or =12)

P(X> or = 12) = P(Z> 12-10/8)

P(Z>=2/8) = P(Z >=0.25)

P(Z) = 1 - P(Z<= 0.25)

We read off Z= 0.25 from the normal distribution table

P(Z) = 1 - 0.0987 = 0.9013

Therefore P(X> or=12) = 0.9013

Note the question was given as an incomplete question the correct and complete question had to be searched online via Google. So the data used are those gotten from the online the Googled question.

3 0
1 year ago
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