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nadezda [96]
1 year ago
13

In a gym class, 1/8 of students play basketball and 5/12 play volleyball. The remaining students play soccer. What fraction of s

tudents play soccer?
Mathematics
2 answers:
Artyom0805 [142]1 year ago
8 0

Answer:

The fraction of students who play soccer is 11/24.

Step-by-step explanation:

Let x be the total number of students in the gym class,

Since, 1/8 of students play basketball,

Thus, the number of students who play baseball = 1/8 of x

=\frac{x}{8}

Also, 5/12 play volleyball,

The number of students who play volleyball = 5/12 of x

=\frac{5x}{12}

Given, students other than playing baseball and volleyball play soccer.

So, the total number of students who play soccer = Total students - ( the students who play baseball + students who play volleyball )

=x-(\frac{x}{8}+\frac{5x}{12})

=x-(\frac{3x}{24}+\frac{10x}{24})

=x-\frac{3x+10x}{24}

= x - \frac{13x}{24}

=\frac{24x-13x}{24}

=\frac{11x}{24}

Hence, the fraction of students who play soccer = Number of students who play soccer / Total students

=\frac{11x/24}{x}

=\frac{11}{24}

kvasek [131]1 year ago
6 0

11/24 is your answer

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miv72 [106K]

case 1,

Let the CP be ₹x,

SP = ₹2400

Profit = SP – CP

= 2400 – x

Profit % = {(2400–x)/ x} × 100%

According to the question,

{(2400–x)/ x} × 100 = 25

=> (2400–x)/ x= 25 /100

=> 100(2400–x) = 25x [ cross multiplication]

=> 240000 – 100x = 25x

=> 240000 = 25x + 100x

=> 240000 = 125x

=> 240000/125 = x

=> x = 1920

So, CP = ₹1920

case 2,

SP = ₹2040

Profit = SP – CP

= 2040 – 1920

= ₹120

profit % = 120/1920 × 100%

= 16%

<h3>Thus, his profit would be 16% if he had sold his goods for ₹2040.</h3>
6 0
1 year ago
The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social me
Rashid [163]

Answer: The proportion of students spending at least 2 hours on social media equals 0.7257 .

Step-by-step explanation:

Given : The typical college freshman spends an average of μ=150 minutes per day, with a standard deviation of σ=50 minutes, on social media.

The distribution of time on social media is known to be Normal.

Let x be the number of minutes spent on social media.

Then, the probability that students spending at least 2 hours (2 hours = 120 minutes as 1 hour = 60 minutes) on social media would be:

P(x\geq120)=1-P(x

Hence, the proportion of students spending at least 2 hours on social media equals 0.7257 .

4 0
2 years ago
Determine the number of atoms in<br> 98.3 g mercury, Hg
Arisa [49]
The answer is 2.95 × 10²³ atoms

Atomic mass is 200.59 g.
So, 1 mole has 200.59 g. Let's calculate how many moles have 98.3 g:
1M : 200.59g = x : 98.3g
x = 98.3 g * 1 M : 200.59 g = 0.49 M

To calculate this, we will use Avogadro's number which is the number of units (atoms, molecules) in 1 mole of substance:

6.023 × 10²³ atoms per 1 mole
<span>How many atoms are in 0.49 mole:
</span>6.023 × 10²³ atoms : 1M = x : 0.49M
x = 6.023 × 10²³ atoms : 1M * 0.49M = 2.95 × 10²³ atoms
8 0
2 years ago
Read 2 more answers
D(-3+x)=kx+9 solve for x
Gnesinka [82]

d(-3 + x) = kx + 9

  • Distribute d inside the parentheses.

-3d + dx = kx + 9

  • Subtract kx from both sides.

-3d + dx - kx = 9

  • Add 3d to both sides.

dx - kx = 9 + 3d

  • Factor x out of dx - kx.

x(d - k) = 9 + 3d

  • Divide both sides by d - k.

x = \frac{9+3d}{d-k}

  • If you want to simplify this even more, factor 3 out of the numerator.
<h3>x = \frac{3(d + 3)}{d-k}</h3>
5 0
2 years ago
PLEASE help!!!! Jackie runs and dances for a total of 55 minutes every day. She dances 25 minutes more than she runs. Part A: Wr
Andrew [12]
Part a:

x + y = 55

y = x + 25

part b:

jackie runs 15 minutes every day.

part c:

it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run

step-by-step explanation:

let's call and while jackie is dancing

let's call x while jackie is running

then we know that jackie runs and dances for a total of 55 minutes every day

this means that:

x + y = 55

we also know that jackie dances 25 minutes more than she runs.

this meant that:

y = x + 25

now we substitute the second equation in the first and solve for the variable x

x + x + 25 = 552x = 55-252x = 30x = 15

jackie runs 15 minutes every day.

now we find the value of the variable -y

15 + y = 55y = 55-15y = 40

note that it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run
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