Ask question

Ask question

All categories

1 year ago

13

In a gym class, 1/8 of students play basketball and 5/12 play volleyball. The remaining students play soccer. What fraction of s

tudents play soccer?

2 answers:

Artyom0805 [142]1 year ago

8 0

Answer:

The fraction of students who play soccer is 11/24.

Step-by-step explanation:

Let x be the total number of students in the gym class,

Since, 1/8 of students play basketball,

Thus, the number of students who play baseball = 1/8 of x

$=\frac{x}{8}$

Also, 5/12 play volleyball,

The number of students who play volleyball = 5/12 of x

$=\frac{5x}{12}$

Given, students other than playing baseball and volleyball play soccer.

So, the total number of students who play soccer = Total students - ( the students who play baseball + students who play volleyball )

$=x-(\frac{x}{8}+\frac{5x}{12})$

$=x-(\frac{3x}{24}+\frac{10x}{24})$

$=x-\frac{3x+10x}{24}$

$= x - \frac{13x}{24}$

$=\frac{24x-13x}{24}$

$=\frac{11x}{24}$

Hence, the fraction of students who play soccer = Number of students who play soccer / Total students

$=\frac{11x/24}{x}$

$=\frac{11}{24}$

kvasek [131]1 year ago

6 0

11/24 is your answer

You might be interested in

It is claimed that 55% of marriages in the state of California end in divorce within the first 15 years. A large study was start

kykrilka [37]

Answer:

0.0045 = 0.45% probability that less than two of them ended in a divorce

Step-by-step explanation:

For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

55% of marriages in the state of California end in divorce within the first 15 years.

This means that $p = 0.55$

Suppose 10 marriages are randomly selected.

This means that $n = 10$

What is the probability that less than two of them ended in a divorce?

This is

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.55)^{0}.(0.45)^{10} = 0.0003$

$P(X = 1) = C_{10,1}.(0.55)^{1}.(0.45)^{9} = 0.0042$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0003 + 0.0042 = 0.0045$

0.0045 = 0.45% probability that less than two of them ended in a divorce

8 0

1 year ago

a water tank holds 24,000 gallons how many hours will it take for two thirds of the water to be used if the water is used at an

melomori [17]

In this question there are several important information's worth noting.Based on these information's the answer can be easily found. It is given that the total capacity of the tank is 24000 gallons. in 24 hours or in 1 day the amount of water used is 650 gallons. The question requires us to find the time it will take to use 2/3 rd of the water in the tank.
then
2/3 rd water in respect to total water in tank = (2/3) * 24000
= 16000
So 2/3 rd water of full tank is equivalent to 16000 gallons.
Now
650 gallons of water is used in = 24 hours
So
16000 gallons of water will be used in = (24/650) * 16000
= 590.77 hours
So it will take 590.77 hours to consume 2/3rd of the total water present in the tank.

6 0

1 year ago

In studying the insurance preferences of homeowners the following conclusions are made: A homeowner is three times as likely to

Ede4ka [16]

Answer:

0.632

Step-by-step explanation:

Given that a homeowner is three times as likely to purchase additional jewelry coverage as additional electronics coverage

If probability of purchasing additional electronics coverage = p, then prob of purchasing jewelry coverage = 3p

The two events are independent hence joint probability is product of these two.

i.e. P(both) = $p(3p) =3p^2$

This is given as 0.2

$3p^2 =0.2\\p = 0.258$

the probability that a homeowner purchases exactly one coverage.

$=P(AUB)-P(A \bigcap B)$

= Prob he purchases I + prob he purchases II-2(prob he purchases both)

$= 0.258+3(0.258)-2(0.2)\\=0.632$

5 0

1 year ago

Draw the number 24 then draw a quick picture to show 24 after you have to regrouped 1 ten as 10 ones explain how both pictures s

Vesnalui [34]

First draw 24 shapes of your choice.

Then, in a different space or below those 24 shapes, draw 10 more shapes twice. So draw 10 shapes and draw 10 more next to them. Finally, draw 4 more shapes with space between them and say "10+10+4=24"

6 0

1 year ago

Solve the given initial value problem and determine how the interval in which the solution exists depends on the initial value y

zalisa [80]

Answer:

y has a finite solution for any value y_0 ≠ 0.

Step-by-step explanation:

Given the differential equation

y' + y³ = 0

We can rewrite this as

dy/dx + y³ = 0

Multiplying through by dx

dy + y³dx = 0

Divide through by y³, we have

dy/y³ + dx = 0

dy/y³ = -dx

Integrating both sides

-1/(2y²) = - x + c

Multiplying through by -1, we have

1/(2y²) = x + C (Where C = -c)

Applying the initial condition y(0) = y_0, put x = 0, and y = y_0

1/(2y_0²) = 0 + C

C = 1/(2y_0²)

So

1/(2y²) = x + 1/(2y_0²)

2y² = 1/[x + 1/(2y_0²)]

y² = 1/[2x + 1/(y_0²)]

y = 1/[2x + 1/(y_0²)]½

This is the required solution to the initial value problem.

The interval of the solution depends on the value of y_0. There are infinitely many solutions for y_0 assumes a real number.

For y_0 = 0, the solution has an expression 1/0, which makes the solution infinite.

With this, y has a finite solution for any value y_0 ≠ 0.

8 0

2 years ago