<u>Answer:</u>
C. Left-handed: 48, Right-handed: 504
D. Left-handed: 30, Right-handed: 315
<u>Step-by-step explanation:</u>
We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.
Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.
Ratio of right handed to left handed students at East Middle School = 
Checking for ratios of the given options:
A. 
B. 
C. 
D. 
E. 
Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.
Step-by-step explanation:
Maths
Bookmark
if 2
2008
−2
2007
−2
2006
+2
2005
=k ⋅2
2005
then the value of k is equal to
Answer
Correct option is
B
3
2
2008
−2
2007
−2
2006
+2
2005
=k⋅2
2005
⇒[2
2008
−2
2006
]−[2
2007
−2
2005
]=k⋅2
2005
⇒2
2006
(2
2
−1)−2
2005
(2
2
−1)=k⋅2
2005
⇒3(2
2006
−2
2005
)=k⋅2
2005
⇒3[2
2005
(2−1)]=k⋅2
2005
⇒3(2
2005
)=k⋅2
2005
On comparing, we get
k=3
Hence, Option B is correct.
For this case we have the following number:
563,626
To answer the question, we must add 10,000 to the given number.
We have then:
563,626 + 10,000
From here, we add both numbers and find the answer.
We have then:
563,626 + 10,000 = 573,626
Answer:
the number that is ten thousand greater than 563,626 is:
573,626
Draw a diagram to illustrate problem as shown below.
Let h = the height of the tree.
Because ΔABC ~ ΔADE, therefore
DE/BC = AD/AB
That is,
h/1.94 = (5.1 + 10.2)/5.1 = 3
h = 1.94*3 = 5.82 m
Answer: 5.82 m
Answer:
30 minutes
Step-by-step explanation:
Let's find how much Bob had covered before Cheryl left.
We need to find Bob's distance in 45 minutes (0.75 hour).
We know D = RT, where D is distance, R is rate, T is time. So,
D = RT
D = 10(0.75) = 7.5 miles
Bob was ahead by 7.5 miles before his wife started.
Now, Bob's rate is 10mph and Cheryl's is 25 mph, that means Cheryl goes 15 miles per hour faster to catch up.
Since, Cheryl will catch up at 15 miles an hour, how long would Cheryl need to catch up 7.5 miles??
Easy!
7.5 is HALF of 15, so Cheryl will required HALF of an hour to catch up, or 30 minutes
